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3 years ago

Find the area of triangle ABC and the area of XYZ. AABC - AXYZ.

Mathematics

1 answer:

beks73 [17]3 years ago

8 0

Answer:

ABC= 60 XYZ=540

Step-by-step explanation:

The area of a triangle is 1/2*base*height so for ABC we need to find the height first. To do this we use pythag theorem, and create the equation 13^2=5^2+height^2 rearranging this we can figure out that sqrt(height)=13^2-5^2. For the base we do 2*5 since there are two congruent line segments both equal to 5. Using this we can do 1/2*12*10=area of ABC

For XYZ we can do 1/2*30*36=area of XYZ, we can do 2*15 since there are 2 congruent 15 length line segments at the base.

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The two figures are proportional. Find the value of x. 36 in. 12 in. LA 10 in.

Alina [70]

36 / x = 12 / 10

12x = 360

x = 30

The correct answer is C. 30 inches.

Hope this helps! :)

3 0

3 years ago

[20points][Precal] Find the cross product of -(3/4)V and (1/2)w if v = <-2, 12, -3> and w = <-7, 4, -6>

Lana71 [14]

$\mathbf v=\langle-2,12,-3\rangle=-2\,\vec i+12\,\vec j-3\,\vec k$
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$\mathbf w=\langle-7,4,-6\rangle=-7\,\vec i+4\,\vec j-6\,\vec k$
$\dfrac12\mathbf w=-\dfrac72\,\vec i+2\,\vec j-3\,\vec k$

$-\dfrac34\mathbf v\times\dfrac12\mathbf w=\begin{vmatrix}\vec i&\vec j&\vec k\\\frac32&-9&\frac94\\-\frac72&2&-3\end{vmatrix}$
$=\left((-9)\times(-3)-\dfrac94\times2\right)\,\vec i-\left(\dfrac32\times(-3)-\dfrac94\times\left(-\dfrac72\right)\right)\,\vec j+\left(\dfrac32\times2-(-9)\times\left(-\dfrac72\right)\right)\,\vec k$
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6 0

3 years ago

what is the side length of the largest square tile that can be used to tile a rectangular floor measuring 12 ft by 38 ft if the

telo118 [61]

The greatest common facter of 12 and 38 is 2 so the answer is:
2 ft

8 0

3 years ago

Splitting a polygon into triangles is a method used in calculating the sum of the interior angles of a polygon. Using this metho

ICE Princess25 [194]

Lets say that a quadrilateral has been divided into two triangles, so the interior angles add up to 2 × 180 = 360°. This pentagon has been divided into three triangles, so the interior angles add up to 3 × 180 = 540°. In the same way, a hexagon can be divided into 4 triangles, a 7-sided polygon into 5 triangles etc.
so your answer is A. 5
(^>^)

5 0

3 years ago

A professor would like to test the hypothesis that the average number of minutes that a student needs to complete a statistics e

Elodia [21]

Answer:

The critical value for this hypothesis test is 6.571.

Step-by-step explanation:

In this case the professor wants to determine whether the average number of minutes that a student needs to complete a statistics exam has a standard deviation that is less than 5.0 minutes.

Then the variance will be, $\sigma^{2}=(5.0)^{2}=25$

The hypothesis to determine whether the population variance is less than 25.0 minutes or not, is:

H₀: The population variance is not less than 25.0 minutes, i.e. σ² = 25.

Hₐ: The population variance is less than 25.0 minutes, i.e. σ² < 25.

The test statistics is:

$\chi ^{2}_{cal.}=\frac{ns^{2}}{\sigma^{2}}$

The decision rule is:

If the calculated value of the test statistic is less than the critical value, $\chi^{2}_{n-1}$ then the null hypothesis will be rejected.

Compute the critical value as follows:

$\chi^{2}_{(1-\alpha), (n-1)}=\chi^{2}_{(1-0.05),(15-1)}=\chi^{2}_{0.95, 14}=6.571$

*Use a chi-square table.

Thus, the critical value for this hypothesis test is 6.571.

7 0

3 years ago

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