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aliya0001 [1]
3 years ago
9

Mr. Shirey is baking cookies to sell for a charity. He bakes 12 dozen cookies in 4 hours. How many cookies

Mathematics
2 answers:
valentina_108 [34]3 years ago
8 0

Answer:

3 dozen, or 36 cookies

Step-by-step explanation:

Find the unit rate

12/4

This will give you 3 dozen cookies per hour, and if you need to know the specific number of cookies just multiply 3 by 12 since there are 12 in a dozen.

Hope this helps ^-^

mixer [17]3 years ago
7 0
She makes 3 dozen, or 36 an hour
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Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

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Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

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Separate the variables

dy/cos²y = lnt dt

Integrate both sides

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y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

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Jsjjss pls help its uRGeNT
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Step-by-step explanation:

The way I did it was, I looked at the chart. The highest it goes is 30 and 210. So for your answer, you have to multiply. 7x30 gives you 210 and there y=7x

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