Tan (Ф/2)=⁺₋√[(1-cosФ)/(1+cosФ)]
if π<Ф<3π/2;
then, Where is Ф/2??
π/2<Ф/2<3π/4; therefore Ф/2 is in the second quadrant; then tan (Ф/2) will have a negative value.
tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]
Now, we have to find the value of cos Ф.
tan (Ф)=4/3
1+tan²Ф=sec²Ф
1+(4/3)²=sec²Ф
sec²Ф=1+16/9
sec²Ф=(9+16)/9
sec²Ф=25/9
sec Ф=-√(25/9) (sec²Ф will have a negative value, because Ф is in the sec Ф=-5/3 third quadrant).
cos Ф=1/sec Ф
cos Ф=1/(-5/3)
cos Ф=-3/5
Therefore:
tan(Ф/2)=-√[(1-cosФ)/(1+cosФ)]
tan(Ф/2)=-√[(1+3/5)/(1-3/5)]
tan(Ф/2)=-√[(8/5)/(2/5)]
tan(Ф/2)=-√4
tan(Ф/2)=-2
Answer: tan (Ф/2)=-2; when tan (Ф)=4/3
Where is the equation or expression?
Answer:
cost per serving can be used as a result of using your head to think
-2,-3
-3, -4
-4, -5
you are showing the line of growth in the graph.
Answer:
97
Step-by-step explanation:
Given the following conditions :
board measuring 1x100, each square is numbered from 1 to 100
Three colors are used to paint the squares from left to right in the sequence :
one blue, two reds and three green squares in a repeated pattern.
What is the highest numbered square that is painted blue?
The sequence of painting is repeated after :
(1 + 2 + 3) = 6 successive squares
Since the number of squares = 100
Maximum complete repetition possible :
100 / 6 = 16 remainder 4
Hence 16 * 6 = 96 (the highest complete sequence terminates on the square numbered 96)
On the 97th square, another sequence begins which is a blue and the 100th square is painted the first of the 3 green colors.
Hence, the highest numbered square that is painted blue is 97
