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GarryVolchara [31]
3 years ago
12

" id="TexFormula1" title=" {8 }^{2} + {10}^{3} \div {5}^{2} " alt=" {8 }^{2} + {10}^{3} \div {5}^{2} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Maslowich3 years ago
5 0

Use PEMDAS

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

8^2+10^3\div5^2=64+1000\div25=64+40=104

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Answer:

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Now we want our circle to pass through point 2, located at a distance of 2 units from the radius of the first circle.

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