The answers to each of the given problems are;
1) Sum of two smallest integers = 23
2) 3x + 6
3) 7.5 m/s²
<h3>How to find the sum of consecutive Integers?</h3>
1) We are told that sum of 4 consecutive integers is increased by 20 and equals 70. Thus, we have;
x + (x + 1) + (x + 2) + (x + 3) + 20 = 70
4x + 26 = 70
4x = 70 - 26
4x = 44
x = 44/4
x = 11
Thus, sum of two smallest integers = 11 + 11 + 1 = 23
2) Let the consecutive odd numbers be;
x, (x + 2) and (x + 4)
Sum of these consecutive odd numbers is;
x + x + 2 + x + 4 = 3x + 6
3) We are given the equation to find the acceleration as;
(v_final)² - (v_initial)² = 2ad
We are given;
v_final = 40 m/s
v_initial = 10 m/s
d = 100 m
Thus;
40² - 10² = 2a(100)
1500 = 200a
a = 1500/200
a = 7.5 m/s²
Read more about sum of integers at; brainly.com/question/17695139
#SPJ1
Here is the answer:
Expanded Form: 50 + 7 + 0.03 + 0.006
Word Form: Fifty plus seven plus zero point zero three plus zero point zero zero six
K + (-4.1) is the exact same as saying k- 4.1, so what you have to do now is put the -4.1 in the opposite side, but with opposite sign too (+)
so k= -9.7 + 4.1
so in order to answer it you have to deduct the number with the lowest value taking in count both as positive and the sign will be the one from the highest value taking both as positive
9.7
-4.1
____
5.6
so 9.7 had a negative sign so the answer to your question is
k = -5.6
i hope i helped you
18/20=27/x
18x=27*20
x=(27*20)/18=30
Answer: 30
Answer:
you should try scanning that one instead of questioning here
