The definition of a Scale Drawing is- <span>A </span>drawing<span> that shows a real object with accurate sizes reduced or enlarged by a certain amount (called the </span>scale<span>). The </span>scale<span> is shown as the length in the </span>drawing<span>, then a colon (":"), then the matching length on the real thing.
</span>Well an example would be- <span>Write the </span>scale<span> of the </span>drawing, 1 cm = 1.5 m, as . Then write a proportion in which each ratio compares centimeters to meters. Let n represent the actual length of the boat. The actual length of the boat is 4.5 m. explaining is a little hard, but u can look up video examples to help u understand better
Step-by-step explanation:
Let "c" be the original number of classrooms.
The 1200/c was the original number of students per classroom.
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Equation:
1200/(c-4) = (1200/c)+10
Multiply thru by c(c-4)
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1200c = 1200(c-4)+10c(c-4)
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1200c = 1200c-4800 + 10c^2-40c
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10c^2-40c-4800 = 0
c^2-4c-480 = 0
Factor:
(c-24)(c+20) = 0
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Positive solution:
c = 24 (# of classrooms originaly planned)
Answer:
5x+4y+8
Step-by-step explanation:
2x+3x=5x
5x+4y+8
The correct answers are:1) sin(x) =
2) tan(x) =
Explanation:Given:

Step 1:
Since, according to the Trigonometric identity:

-- (1)
Step 2:
Plug in the value of cos(x) in equation (1):

Step 3:
Take square-root on both sides:

sin(x) =

Now to find the tan(x), we would use the following formula:
tan(x) =

--- (2)
Plug in the values of sin(x) and cos(x) in equation (2):
tan(x) =

Hence tan(x) =