Ashley says that the CDE ≅ FGH by the HL postulate.
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The graph would have to look like the attachment I attached to this comment. If you can't see it then the graph will go through the y-intercept of -2 and the x-intercept of 3.
Explanation: Already we can tell that the line will go through -2 as the y-intercept. So we have to take the slope and apply it to the -2. The slope is in rise over run form. We rise 2 times. And then go to the right 3 times. We can do the same but backwards. Go down 2 times. and then go left 3 times. Do it twice in both ways and you have your line.
Explanation: Already we can tell that the line will go through -2 as the y-intercept. So we have to take the slope and apply it to the -2. The slope is in rise over run form. We rise 2 times. And then go to the right 3 times. We can do the same but backwards. Go down 2 times. and then go left 3 times. Do it twice in both ways and you have your line.