Answer:
A. 0.9510
B. 0.0480
C. 0.0490
D. No, I would not feel comfortable accepting the shipment if one item was found defective, because the probability is quite small to obtain 1 or more defective items.
You distribute the -4 with the -8x and -8 which results in 32x+32.
Answer:
AC, AB, BC
Step-by-step explanation:
You just put the two angles together
^^^got it right on edg
Answer
The triangle in the figure 4 is correct .
Reason
by using the trignometric identity

Thus


Now in the figure (1)


on simplify

thus side length measures in the figure (1) is not correct .
Now in the figure (2)

thus side length measures in the figure (2) is not correct .
Now in the figure (3)

thus side length measures in the figure (3) is not correct .
Now in the figure (4)

Therefore the figure (4) is correct triangle has side length measures that could be correct
Hence proved