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Serhud [2]
3 years ago
13

If 5|x − 1| = 20, then x = 1 or 5 6 or –8 –2 or 4 5 or –3 Please help

Mathematics
1 answer:
anygoal [31]3 years ago
5 0

Answer:

Step-by-step explanation:

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In the given figure, if AOB is a straight line, then ∠BOC is
DedPeter [7]

Answer:

acute angle.

Step-by-step explanation:

because it is 60 degree

7 0
2 years ago
Read 2 more answers
Four students about to purchase concert tickets for $18.50 for each ticket discover that they may purchase a block of 5 tickets
soldier1979 [14.2K]
So, its 18.5 per person
<span><span>
80/5=16
18.5-16=2.5

They would each save 2.5 dollars each.</span></span>
7 0
3 years ago
The amount of time a passenger waits at an airport check-in counter is random variable with mean 10 minutes and standard deviati
Stolb23 [73]

Answer:

(a) less than 10 minutes

= 0.5

(b) between 5 and 10 minutes

= 0.5

Step-by-step explanation:

We solve the above question using z score formula. We given a random number of samples, z score formula :

z-score is z = (x-μ)/ Standard error where

x is the raw score

μ is the population mean

Standard error : σ/√n

σ is the population standard deviation

n = number of samples

(a) less than 10 minutes

x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Therefore, the probability that the average waiting time waiting in line for this sample is less than 10 minutes = 0.5

(b) between 5 and 10 minutes

i) For 5 minutes

x = 5 μ = 10, σ = 2 n = 50

z = 5 - 10/2/√50

z = -5 / 0.2828427125

= -17.67767

P-value from Z-Table:

P(x<5) = 0

Using the z table to find the probability

P(z ≤ 0) = P(z = -17.67767) = P(x = 5)

= 0

ii) For 10 minutes

x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Hence, the probability that the average waiting time waiting in line for this sample is between 5 and 10 minutes is

P(x = 10) - P(x = 5)

= 0.5 - 0

= 0.5

3 0
3 years ago
Refer to the sample data for​ pre-employment drug screening shown below. If one of the subjects is randomly​ selected, what is t
RoseWind [281]

Answer:

0.193877

Step-by-step explanation:

The data given to us is

<em><u>Pre-Employment Drug Screening Results</u></em>

                    Positive test result                 Negative test result

                    Drug Use Is Indicated            Drug Use Is Not Indicated

Subject Uses Drugs:            38                                         12

Subject Is Not a drug user: 19                                         29

Now the total of this is = 38+19+12+29= 98

Now the probability of false positive is = 19/98= 0.193877

The <u>Subject Is Not a drug user </u>  would suffer from a false positive. He is not a user and has a positive result.

7 0
3 years ago
Zelma buys p pounds of bananas for $0.40 per pound she pays the clerk with a $20 bill the clerk subtract the total cost of the b
Sloan [31]
You didnt include the (presumably) multiple choice answers. My guess is that the answer would be along the lines of: 20 - (P times .40)
7 0
3 years ago
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