Remark
The very first thing you should do is graph the function, which I have done. It is at the bottom of this answer.
Step One
Where is the hole and what kind is it? This graph has a hole at x = 2. At that point the function is 0/0. A hole is defined as the point created by a zero in one of the factors that is the same in the numerator and denominator. Both = 0.
Step 2
Find the vertical asymptote.
That occurs when denominator alone has a factor that is = 0. In this case when x = 3 the whole equation blows up (or down) and you have a vertical asymptote. The graph is discontinuous at this point.
Step three
Find the horizontal Asymptote.
Horizontal assymptotes occur when (in this case) the power of the factors in the denominator exceeds the power of the factors in the numerator. In this case that is true and the horizontal assymptote occurs around the line y = 0.
Answer:
At a certain pizza parlor,36 % of the customers order a pizza containing onions,35 % of the customers order a pizza containing sausage, and 66% order a pizza containing onions or sausage (or both). Find the probability that a customer chosen at random will order a pizza containing both onions and sausage.
Step-by-step explanation:
Hello!
You have the following possible pizza orders:
Onion ⇒ P(on)= 0.36
Sausage ⇒ P(sa)= 0.35
Onions and Sausages ⇒ P(on∪sa)= 0.66
The events "onion" and "sausage" are not mutually exclusive, since you can order a pizza with both toppings.
If two events are not mutually exclusive, you know that:
P(A∪B)= P(A)+P(B)-P(A∩B)
Using the given information you can use that property to calculate the probability of a customer ordering a pizza with onions and sausage:
P(on∪sa)= P(on)+P(sa)-P(on∩sa)
P(on∪sa)+P(on∩sa)= P(on)+P(sa)
P(on∩sa)= P(on)+P(sa)-P(on∪sa)
P(on∩sa)= 0.36+0.35-0.66= 0.05
I hope it helps!
(a) Let h and d represent the numbers of packages of Hamburger and hotDog buns, respsectively.
.. h +d = 12 . . . . . . . . . . . . the family brought 12 packages of buns
.. 2.00h +1.50d = 20 . . . . each family contributed $20
(b) Double the first equation and subtract the second one
.. 2(h +d) -(2h +1.5d) = 2(12) -(20)
.. 0.5d = 4 . . . . . . . . . . . . . . . . . . . . . simplify
.. d = 8 . . . . . . . . . . . . . . . . . . . . . . . . multiply by 2
.. h = 12 -d = 4
They brought 4 packages of hamburger buns and 8 packages of hotdog buns.
(c) The number of hotdog bun packages cannot exceed 20/1.5 = 13.3 or the budget will be exceeded.
(d) It depends on the relationship of the variables to the ordered pair.
.. (h, d) = (5, 7) would mean 5 hamburger bun packages and 7 hotdog bun packages
.. (d, h) = (5, 7) would mean 7 hamburger bun packages and 5 hotdog bun packages
(e) Their cost for that purchase would be 7*2.00 +4*1.50 = 14.00 +6.00 = 20. That purchase meets the cost constraint, so is fair from a cost contribution point of view. Whether it is fair from a menu point of view depends on the number of hamburgers and hotdogs that need buns.
Let Sam be (S+8) years while his sister is S years.
S(S+8) = 105
S^2+8S-105 = 0
(S+15)(S-7) = 0
Sam’s sister is 7 years and Sam is 15 years old.
Answer:
34,000 hope it helps
Step-by-step explanation: