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katovenus [111]
3 years ago
12

Please help apex ansers

Mathematics
1 answer:
goblinko [34]3 years ago
6 0
The factorization of A is y = (x - 8)(x + 7).
The factorization of B is y = (x + 1)(x - 4)(x - 5)

In order to find these, you must first find where each graph crosses the x-axis. In the first problem it does so at 8 and -7. In order to find the correct parenthesis for those, you need to write it out as a statement and then solve for 0. 

x = 8 ---> subtract 8 from both sides
x - 8 = 0
This means we use (x -  8) in our factorization. 

You then need to repeat the process until you have all the pieces. In the second problem, there will be 3 instead of 2 since it crosses the axis 3 times. 
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What's the total Cents?
saveliy_v [14]

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

Answer:

Let's see...

Step-by-step explanation:

  • The first coin is a quarter.
  • The second, third, fourth, and fifth coins are dimes.
  • The sixth, seventh, and eighth coins are nickels.

That being said, what is the total value of the cents?

cents    =  ¢

<u>Values:</u>

Quarter = 25 ¢

Dime     = 10 ¢

Nickel   = 5 ¢

So,

1 quarter + 4 dimes + 3 nickels    = total cents

25 + 10 + 10 + 10 + 10 + 5 + 5 + 5 = total cents

25 + 40 + 5 + 5 + 5                       = total cents

25 + 40 + 15                                  = total cents

25 + 55                                         = total cents

80                                                  = total cents

<h3><em>Our answer is 80¢</em></h3><h3><em /></h3>

I hope this helps!

- sincerelynini

8 0
3 years ago
Please hurry! I'm so confused
Varvara68 [4.7K]

Answer:

Step-by-step explanation:

The general equation is

y = 2.49x + 24.99

The number of cones bought is x

The cake cost is 24.99

The total cost is y

===========

So the meaning of (5,37.44) is that she bought 5 cones and 1 cake. Let's just check that out.

Check

y = 2.49*5 + 24.99

y = 12.45 + 24.99

y = 37.44

So the total cost (y) of 5 cones (2.49 each) and 1 cake ($24.99) is 37.44

5 0
3 years ago
An air traffic controller spots two airplanes at the same altitude converging to a point as they fly at right angles to each oth
sattari [20]
They are traveling at right angles to each other so we can say one is traveling north to south and the other west to east.  Then we can say that there positions, y and x are:

y=150-600t  x=200-800t

By using the Pythagorean Theorem we can find the distance between these two planes as a function of time:

d^2=y^2+x^2, using y and x from above

d^2=(150-600t)^2+(200-800t)^2

d^2=22500-180000t+360000t^2+40000-320000t+640000t^2

d^2=1000000t^2-500000t+62500

d=√(1000000t^2-500000t+6250)

So the rate of change is the derivative of d

dd/dt=(1/2)(2000000t-500000)/√(1000000t^2-500000t+6250)

dd/dt=(1000000t-250000)/√(1000000t^2-500000t+6250)

So the rate depends upon t and is not a constant, so for the instantaneous rate you would plug in a specific value of t...

...

To find how much time the controller has to change the airplanes flight path, we only need to solve for when d=0, or even d^2=0...

1000000t^2-500000t+62500=0

6250(16t^2-8t+1)=0

6250(16^2-4t-4t+1)=0

6250(4t(4t-1)-1(4t-1))=0

6250(4t-1)(4t-1)=0

6250(4t-1)^2=0

4t-1=0

4t=1

t=1/4 hr

Well technically, the controller has t<1/4 because at t=1/4 impact will occur :)


7 0
3 years ago
In a state where license plates contain six digits, what is the probability that the license number of a randomly selected car h
andre [41]

Answer:

Step-by-step explanation:

Given : In a state where license plates contain six digits.

Probability of that a number is 9 = \dfrac{1}{10}   [Since total digits = 10]

We assume that each digit of the license number is randomly selected  .

Since each digit in the license plate is independent from the other  and there is only two possible outcomes for given case (either 9 or not), so we can use Binomial.

Binomial probability formula:  P(X=x)=^nC_xp^x(1-p)^{n-x}

, where n= total trials , p = probability for each success.

Let x be the number of 9s in the license plate number.

X\sim Bin(n=6, p=\dfrac{1}{10}})

Then, the probability that the license number of a randomly selected car has exactly two 9's will be :

P(X=2)=^6C_2(\dfrac{1}{10})^2(1-\dfrac{1}{10})^{6-2}\\\\=\dfrac{6!}{2!(6-2)!}(\dfrac{1}{100})(\dfrac{9}{10})^4=0.098415

Hence, the required probability = 0.098415

5 0
3 years ago
H (x)=x^2+ 8x+7 , what function family does this equation belong to?
Semenov [28]

Answer:

Algebra

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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