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DaniilM [7]
3 years ago
12

Solve the system of equations: y = 2x y = x2 - 3 please help asap

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
7 0

Answer:

y=x squared-2x-3

Step-by-step explanation:

I hope this helps

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Applying properties to write equivalent expressions for 2x+5y+5(2x+5y)
levacccp [35]

Solving expression 2x+5y+5(2x+5y) we get 12x+30y

Step-by-step explanation:

We need to solve the expression:

2x+5y+5(2x+5y)

Solving:

Multiplying 5 with terms inside the bracket:

2x+5y+5(2x+5y)\\=2x+5y+10x+25y\\Combining\,\,like\,\,terms:\\=2x+10x+5y+25y\\=12x+30y

So, Solving expression 2x+5y+5(2x+5y) we get 12x+30y

Keywords: Solving Expressions

Learn more about Solving Expressions at:

  • brainly.com/question/11207748
  • brainly.com/question/2154850
  • brainly.com/question/4279146

#learnwithBrainly

7 0
2 years ago
Given: A, B, and C What is the value of X in the matrix equation AX + B = C?
Ksju [112]

Answer:

Option (2)

Step-by-step explanation:

Given expression is, AX + B = C

A=\begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}

B=\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix}

C=\begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}

AX + B = C

AX = C - B

C - B = \begin{bmatrix}-42 & -20\\ 5 & 4\end{bmatrix}-\begin{bmatrix}-7 & -9\\ 4 & -1\end{bmatrix} = \begin{bmatrix}-42+7 & -20+9\\ 5-4 & 4+1\end{bmatrix}

C - B = \begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}

Let  X=\begin{bmatrix}a & b\\ c & d\end{bmatrix}

AX = \begin{bmatrix}-3 & -4\\ 1 & 0\end{bmatrix}\times \begin{bmatrix}a & b\\ c & d\end{bmatrix}

     = \begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}

Since AX = C - B

\begin{bmatrix}(-3a-4c) & (-3b-4d)\\ a & b\end{bmatrix}=\begin{bmatrix}-35 & -11\\ 1 & 5\end{bmatrix}

Therefore, a = 1, b = 5

(-3a - 4c) = -35

3(1) + 4c = 35

3 + 4c = 35

4c = 32

c = 8

And (-3b - 4d) = -11

3(5) + 4d = 11

4d = -4

d = -1

Therefore, Option (2). X = \begin{bmatrix}1 & 5\\ 8 & -1\end{bmatrix} will be the answer.

7 0
3 years ago
DESPERATE! PLEASE HELP!! BRAINLIEST! Show how you got answer please!
frosja888 [35]
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count all the square boxes. count the boxes covering more than half and leave the boxes covering less than half. I hope it's correct.
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2 years ago
Round 0.83,to the nearest thousandths<br> NEED HELP IMMEDIATELY!!!
Dafna1 [17]
0.008 i think this is the answer
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2 years ago
Can someone help me with this question please.
Daniel [21]

Answer:

c

Step-by-step explanation:

*View attached graph*

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2 years ago
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