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7nadin3 [17]
2 years ago
14

Please help im desperate

Mathematics
1 answer:
gogolik [260]2 years ago
3 0

Answer:

m

∠

N

=

67

∘

,

and

,

m

∠

P

=

113

∘

.

Explanation:

By what is given,  

m

∠

M

+

m

∠

N

=

90

∘

...

...

...

...

...

(

1

)

, and,

m

∠

N

+

m

∠

P

=

180

∘

...

...

...

...

...

...

...

...

.

(

2

)

Since,  

m

∠

M

=

23

∘

, by (1), we get,  

m

∠

N

=

90

∘

−

23

∘

=

67

∘

.

Using this in  

(

2

)

, we get,  

m

∠

P

=

180

∘

−

67

∘

=

113

∘

.

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Chara sold 52 boxes of candy for her marching band fundraiser. The large box costs $3.50 each and the small box costs $1.75 each
Ahat [919]

Answer:

The number of boxes of candy sold are:

40 small boxes and

12 large boxes of candy.

Step-by-step explanation:

Let the number of small boxes sold = x

Let the number of large boxes sold = y

we are given the following information:

x + y = 52 - - - - - -(1)   (Chara sold 52 boxes of candy)

3.5(y) + 1.75(x) = 112 - - - - - - (2)   (Chara sold $112 worth of candy)

From the two equations above, x and y can be solved as follows:

x + y = 52   - - - - - -(1)

x = 52 - y    - - - - - - (3)

putting the value if x in equation (3) to replace x in equation (2);

3.5(y) + 1.75(x) = 112 - - - - - - (2)

3.5(y) + 1.75(52 - y) = 112

3.5y + 91 - 1.75y = 112

(3.5y - 1.75y) + 91 = 112

1.75y = 112 - 91 = 21

y = 21 ÷ 1.75 = 12

y = 12

Now, let us put the value of y into equation (3)

x = 52 - y    - - - - - - (3)

x = 52 - 12 = 40

Therefore,

40 small boxes and 12 large boxes of candy were sold.

7 0
3 years ago
WILL GIVE BRAINIEST AND POINTS :
crimeas [40]

Answer:

BE = FC = 3 inches, EF = 2 inches

Step-by-step explanation:

The sum of angles A and D is 180°, so the sum of their half-angles is 90°. That is, half of A plus half of B add to 90°, so the bisector from B intersects AE at a right angle. Call that point of intersection X.

Then angle ABX = angle EBX, so triangle ABX is congruent to triangle EBX. Sides AB and BE are corresponding sides of congruent triangles.

The same argument applies to sides DC and CF.

Thus we have BE = CF = 3 inches, and EF is the left-over distance, 2 inches.

7 0
3 years ago
What is the value of z?
nirvana33 [79]

its 30 because if you add the numbers together then you get 90, then you do 180-90 and get 90, divide 90 by 3 and get 30

5 0
2 years ago
MARKING BRAINLIST! PLEASE HELP!
Leviafan [203]

Answer:

\boxed {\boxed {\sf C. \ 4 \ inches}}

Step-by-step explanation:

Circumference is the perimeter of a circle. It can be found using the formula:

c= \pi d

However, we are given the radius.

  • The radius measures from the center to the edge of the circle.
  • The diameter measures from edge to edge through the center.
  • So, the diameter is twice the radius, or d=2r

The formula can be rewritten as:

c= \pi 2 r

We know the circumference is 25.12 inches.

25.12 \ in = \pi 2r

Let's round pi to 3.14

25.12 \ in = (3.14) 2r

We want to solve for the radius, so we must isolate it.

Divide both sides by 3.14 because the inverse of multiplication is division.

25.12 \ in / 3.14= (3.14 ) 2r  / 3.14

8 \ in = 2r

Divide both sides by 2.

8 \ in / 2 = 2r/2

4 \ in = r

The radius of the disc is <u>4 inches.</u>

6 0
3 years ago
Brook makes this conjecture: Because the angles are equal, the proportion of area of each sector relative to the area of the giv
AnnZ [28]

Answer:

The Brooks conjecture is true as the proportion of the area of a sector to the area of a circle is only dependent on the angle.

Step-by-step explanation:

The area of a sector for a radius r and an angle θ is given as

\Delta Sector=\dfrac{1}{2}r^2\theta

Whereas the area of a circle for a radius r is given as

\Delta Circle=\pi r^2

Now the ratio is given as

\dfrac{\Delta Sector}{\Delta Circle}=\dfrac{\dfrac{1}{2}r^2\theta}{\pi r^2}

Here as r is the radius of the circle and it is the same therefore the above ratio is simplified to

\dfrac{\Delta Sector}{\Delta Circle}=\dfrac{\theta}{2\pi }

Here as π is constant the only variable here is θ. Thus according to Brooks conjecture when the angles are equal, the proportion of area of each sector relative to the area of the given circle is also equal is true.

6 0
3 years ago
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