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Naddik [55]
2 years ago
15

A skier descends a mountain at an angle of 35.0º to the horizontal. If the mountain is 235 m long, what are the horizontal and v

ertical components of the skier's displacement? (Use trigonometry to solve.)

Physics
2 answers:
Zina [86]2 years ago
7 0

Answer:

X = 192.5 m Y = 134.8 m

Explanation:

Horizontal Displacement

X = 235cos35

X = 192.5 m

Vertical Displacement

Y = 235sin35

Y = 134.8 m

Ipatiy [6.2K]2 years ago
6 0
Make sure your calculator is in degrees mode

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A train slows from 60m/s to 20m/s in 50s
Dovator [93]

Answer:

a = -4/5 m/s^2

Explanation:

Acceleration = change in velocity / time

change in velocity = final velocity - initial velocity

a = (20 m/s - 60 m/s) / 50 s

a = -40 m/s / 50 s

a = -4/5 m/s^2

hope this helps! <3

7 0
1 year ago
Read 2 more answers
If pressure is increased from 200 kPa to 300 kPa, and the original volume of gas was 1.5 L, what is the new volume? Assume the t
Oxana [17]

Answer:

The answer to your question is:      V2 = 1 l

Explanation:

Data

P1 = 200 kPa

P2 = 300 kPa

V1 = 1.5 l

V2 = ?

Formula

                          P1V1 = P2V2

                          V2 = (P1V1) / P2

                          V2 = (200 x 1.5) / 300

                          V2 = 1 l

6 0
3 years ago
Explain what the star looks like to Jane
S_A_V [24]
The star looks like a desirable hunk of masculinity to Jane. But to John, the star looks like a wimpy momma's boy who might compete with him for Jane's attention. Jane and John have different impressions of the star because of their gender-specific instincts that have evolved during thousands of millenia of human evolution.
7 0
3 years ago
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A fire hose held near the ground shoots water at a speed of 6.5 m/s. At what angle(s) should the nozzle point in order that the
valina [46]
The speed of water can be split into vertical and horizontal speed components:
v_x = 6.5 cos \theta \\ v_y = 6.5 sin \theta

Due to the force of gravity, the y component will be parabolic. The x component will be linear:
y(t) = -4.9t^2 + (6.5sin \theta) t \\  \\ x(t) = (6.5 cos \theta) t
To find when the water hits the ground 2.5m away, set y= 0 and x = 2.5
-4.9t^2 + (6.5sin \theta) t=0 \\  \\ t = \frac{6.5}{4.9} sin \theta \\ \\(6.5 cos \theta)(\frac{6.5}{4.9} sin \theta) = 2.5 \\  \\ sin \theta cos \theta = 0.29 \\  \\ sin 2\theta = 0.58 \\  \\ 2\theta = 35.4, 144.6 \\  \\ \theta = 17.7,72.3
8 0
3 years ago
A circular loop with radius r is rotating with constant angular velocity ω in a uniform electric field with magnitude E. The axi
inn [45]

Answer:

\Phi_{E} = E\pi r^2 \omega t

Explanation:

The electric flux is defined as the multiple of electric field and the area that the electric field passes through, such that

\Phi_{E} = \vec{E}\vec{A}

When calculating the electric flux, the angle between the directions of electric field and the area becomes important, especially if the angle is changing with time.

The above formula can be rewritten as follows

\Phi_{E} = EA\cos(\theta)

where θ is the angle between the electric field and the area of the loop. Note that, the direction of the area of the loop is perpendicular to the plane of the loop.

If the loop is rotating with constant angular velocity ω, then the angle can be written as follows

\theta = \omega t

At t = 0, cos(0) = 1 and the electric flux through the loop is at its maximum value.

Therefore the electric flux can be written as a function of time

\Phi_{E} = E\pi r^2 \omega t

3 0
3 years ago
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