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alexgriva [62]
3 years ago
9

A mass is suspended on a vertical spring. Initially, the mass is in equilibrium. Then, it is pulled downward and released. The m

ass then moves up and down between the "top" and the "bottom" positions. By definition, the period of such motion is the time interval it takes the mass to move:Mark all the correct statements among those provided below. a. from the top position to the bottom. b. from the equilibrium position to the bottom. c. from the bottom position to the top. d. from the equilibrium position to the bottom and then back to the equilibrium. e. from the equilibrium position to the top and then back to the equilibrium. f. from the equilibrium position to the top. g. from the top position to the bottom and then back to the top. h. from the bottom position to the top and then back to the bottom.
Physics
1 answer:
anastassius [24]3 years ago
8 0

Answer:

d. from the equilibrium position to the bottom and then back to the equilibrium.

g. from the top position to the bottom and then back to the top.

h. from the bottom position to the top and then back to the bottom.

Explanation:

It is the case of SHM or Simple Harmonic Motion. Firstly, there is a need to understand the time interval or time period. The standard definition of time period in simple harmonic motion is

"the time period required for the system to complete its one cycle"

Now one have to consider that  the system given above, the motion of mass attached to spring will follow the path of motion from equilibrium point to bottom to equilibrium point to top, then equilibrium point to the bottom and so on.

to choose right answer you must have to consider the option, in which the starting point and ending point of the mass is same. If mass starts from top, the time it will take to reach on top again, will be defined as its time period and so in the case of bottom or equilibrium as starting point. Hence, "d", "g" and "h" are right answers.

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You drive on Interstate 10 from San Antonio to Houston, half the time at 72 km/h and the other half at 98 km/h. On the way back
zimovet [89]

Answer: a. 85km/hr b.82.3km/hr

c. 84km/hr

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Half time 1hr was covered with speed of 72km/hr

Distance = speed*time=72km/hr *1hr

=72km

So too with the second half of 1hr covered with speed of 98km/hr

Distance = 98km

Total distance from Houston to San Antonio is 98+72 =170km

a. Average speed from San Antonio to Houston is

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b.half distance from Houston to San Antonio which is 170km/2

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t = dist/speed

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Remaining 85 km covered with a speed of 98km/hr

Time = 85/98 = 0.88*60min

= 52 mins

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3 years ago
Calculate the RMS voltage of the following waveforms with 10 V peak-to-peak:
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Answer:

a) T=0.01s

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c) T=0.00001s

Explanation:

From the question we are told that:

Given Frequencies

a. 100 Hz,

b. 1 kHz,

c. 100 kHz.

Generally the equation for Waveform Period is mathematically given by

T=\frac{1}{f}

Therefore

a)

For

T=100 Hz

T=\frac{1}{100}

T=0.01s

b)

For

F=1kHz

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T=0.001s

c)

For

F=100kHz

T=\frac{1}{100*100}

T=0.00001s

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