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alexgriva [62]
3 years ago
9

A mass is suspended on a vertical spring. Initially, the mass is in equilibrium. Then, it is pulled downward and released. The m

ass then moves up and down between the "top" and the "bottom" positions. By definition, the period of such motion is the time interval it takes the mass to move:Mark all the correct statements among those provided below. a. from the top position to the bottom. b. from the equilibrium position to the bottom. c. from the bottom position to the top. d. from the equilibrium position to the bottom and then back to the equilibrium. e. from the equilibrium position to the top and then back to the equilibrium. f. from the equilibrium position to the top. g. from the top position to the bottom and then back to the top. h. from the bottom position to the top and then back to the bottom.
Physics
1 answer:
anastassius [24]3 years ago
8 0

Answer:

d. from the equilibrium position to the bottom and then back to the equilibrium.

g. from the top position to the bottom and then back to the top.

h. from the bottom position to the top and then back to the bottom.

Explanation:

It is the case of SHM or Simple Harmonic Motion. Firstly, there is a need to understand the time interval or time period. The standard definition of time period in simple harmonic motion is

"the time period required for the system to complete its one cycle"

Now one have to consider that  the system given above, the motion of mass attached to spring will follow the path of motion from equilibrium point to bottom to equilibrium point to top, then equilibrium point to the bottom and so on.

to choose right answer you must have to consider the option, in which the starting point and ending point of the mass is same. If mass starts from top, the time it will take to reach on top again, will be defined as its time period and so in the case of bottom or equilibrium as starting point. Hence, "d", "g" and "h" are right answers.

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A 0.80 kg basketball traveling upward at 5.0 m/s impacts an 8.0 10 kg tennis ball traveling downward at 5.0 m/s. The basketball’
vlabodo [156]

To solve this problem we will apply the concepts related to the conservation of momentum. This can be defined as the product between the mass and the velocity of each object, and by conservation it will be understood that the amount of the initial momentum is equal to the amount of the final momentum. By the law of conservation of momentum,

m_1u_1+m_2u_2 = m_1v_1+m_2v_2

Here,

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8333 = 2500*9.8\mu

\mu = \frac{8333}{2500 * 9.8} = 0.34

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3 years ago
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