1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alexgriva [62]
3 years ago
9

A mass is suspended on a vertical spring. Initially, the mass is in equilibrium. Then, it is pulled downward and released. The m

ass then moves up and down between the "top" and the "bottom" positions. By definition, the period of such motion is the time interval it takes the mass to move:Mark all the correct statements among those provided below. a. from the top position to the bottom. b. from the equilibrium position to the bottom. c. from the bottom position to the top. d. from the equilibrium position to the bottom and then back to the equilibrium. e. from the equilibrium position to the top and then back to the equilibrium. f. from the equilibrium position to the top. g. from the top position to the bottom and then back to the top. h. from the bottom position to the top and then back to the bottom.
Physics
1 answer:
anastassius [24]3 years ago
8 0

Answer:

d. from the equilibrium position to the bottom and then back to the equilibrium.

g. from the top position to the bottom and then back to the top.

h. from the bottom position to the top and then back to the bottom.

Explanation:

It is the case of SHM or Simple Harmonic Motion. Firstly, there is a need to understand the time interval or time period. The standard definition of time period in simple harmonic motion is

"the time period required for the system to complete its one cycle"

Now one have to consider that  the system given above, the motion of mass attached to spring will follow the path of motion from equilibrium point to bottom to equilibrium point to top, then equilibrium point to the bottom and so on.

to choose right answer you must have to consider the option, in which the starting point and ending point of the mass is same. If mass starts from top, the time it will take to reach on top again, will be defined as its time period and so in the case of bottom or equilibrium as starting point. Hence, "d", "g" and "h" are right answers.

You might be interested in
To the speaker makes the sound louder.
Damm [24]

Answer:

the right control panel.

Place the listener at a certain distance away from the speakers. Slowly move the listener up and down. What do y

Explanation:

4 0
2 years ago
Calculate the speed (in m/s) of an electron and a proton with a kinetic energy of 1.85 electron volt (eV). (The electron and pro
Natali5045456 [20]

Answer:

ve = 8.06 x 10^5 m/s

vp = 1.882 x 10^4 m/s

Explanation:

K = 1.85 eV = 1.85 x 1.6 x 10^-19 J = 2.96 x 10^-19 J

me = 9.11 ✕ 10^-31 kg,

mp = 1.67 ✕ 10^-27 kg

Let the speed of electron is ve and the proton is vp.

For electron :

K = 1/2 me x ve^2

2.96 x 10^-19 = 0.5 x 9.11 x 10^-31 x ve^2

ve^2 = 6.498 x 10^11

ve = 8.06 x 10^5 m/s

For proton:

K = 1/2 mp x vp^2

2.96 x 10^-19 = 0.5 x 1.67 x 10^-27 x vp^2

vp^2 = 3.5449 x 10^8

vp = 1.882 x 10^4 m/s

6 0
2 years ago
The earliest radio broadcasts on Earth were emitted about 100 years ago. Approximately where are these initial radio waves now?
Gala2k [10]

Answer:

100 ly are d=9.454255\times10^{17}m

Explanation:

The speed of light is, by definition (we define this and derive a definition of distance from there nowadays), c=299792458m/s. We want to know, at this speed, how much distance the radio signals travel in 100 years. Since each year has 365 days (not a leap one though), each day has 24 hours, each hour has 60 minutes and each minute has 60 seconds, the number of seconds in a year will be (365)(24)(60)(60)=31536000, so the distance traveled by the waves in 100 years will be:

d=vt=(299792458m/s)(100)(31536000s)=9.454255\times10^{17}m, which, of course, are 100 light years.

3 0
3 years ago
A 75.0 Ohm resistor uses 0.285 W of power. What is the voltage across the resistor?
Brilliant_brown [7]

Answer:4.62

Explanation:

Acellus

6 0
2 years ago
When a car drives over a speed bump and oscillates up and down in simple harmonic motion, at which position during the motion is
Oksana_A [137]
Using the second Law of Newton, F = m * a, you know that acceleration is maximum when the force is maximum.


Using Hooke's Law, F = K Δx, you know that the force is maximum when the displacement from the equilibrium (Δx) is maximum.


So the answer is that the acceleration is maximum at the maximum amplitude x = a.
3 0
3 years ago
Other questions:
  • A 75.0 kg ladder that is 3.00 m in length is placed against a wall at an angle theta. The center of gravity of the ladder is at
    9·1 answer
  • When a force is applied through a distance , work is done
    13·1 answer
  • For the following situations, describe the contact and non-contact forces that are involved.
    10·2 answers
  • In both ionic and molecular bonds, the resulting compound is stabilized because
    10·1 answer
  • Sam moves an 800 N wheelbarrow 5 meters in 15 seconds. How much work did he do?
    5·1 answer
  • Anybody please help me in PHYSICS WAVE.
    11·1 answer
  • A road map is an example of a
    5·1 answer
  • 1. Through the law of gravity, Newton showed that two objects attracted by gravity actually orbit
    9·1 answer
  • Uranium-235 Fission
    5·1 answer
  • Microscopes are used to study the structures of rocks. Over time, microscopes have become more and more powerful.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!