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Nimfa-mama [501]
4 years ago
12

The equation of the line passing through the points (-1, 8) and (3, 16) can be expressed as y = mx + b. Give the value of b.

Mathematics
2 answers:
vichka [17]4 years ago
4 0

The slope -intercept form of linear equation is y=mx+b.

Where m= slope and b=y-intercept.

Formula to find m is,

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

The line passes through (-1, 8) and (3, 16) . So, we can plug in x1=-1, y1=8, x2=3 and y2=16 in the above formula. So,

m=\frac{16-8}{3-(-1)}

m=\frac{8}{3+1}

m=\frac{8}{4}

So, m=2

Now we can plug in m=2, x=3 and y=16 in y=mx+b to get the value of b. So,

16=2*3+b

16=6+b

16-6=b

So, b=10.

gizmo_the_mogwai [7]4 years ago
4 0
B=10. I did all the work but I don’t feel like typing it lol
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Answer:

$420

Step-by-step explanation:

To work this out you would need to find the 25% decrease of 560. To do this you would first divide 25 by 100, which gives you 0.25. Then you would minus 0.25 from 1, which gives you 0.75. This is because when finding percentage decreases you would first have to convert it into a decimal. Then you would have to minus it from 1 , to make sure that it will be a 25% decrease not a 75% decrease. Then you would multiply 560 by 0.75, which gives you 420.

1) Divide 25 by 100.

25/100=0.25

2) Minus 0.25 from 1.

1-0.25=0.75

3) Multiply 560 by 0.75.

560*0.75=$420

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Find the point, M, that divides segment AB into a ratio of 2:3 if A is at (0.15) and B is at (20.0)
timama [110]

Answer:

M = (8,9)

Step-by-step explanation:

Notice that the points (0,15), and (20,0) form with the origin of coordinates (0,0),  a right angle triangle (please see attached image). This triangle has twon perpendicular sides of length 15 and 20 respectively. Therefore, we can find the length of the segment that joins points A (0,15) and B (20,0) by finding the length of the hypotenuse in a right angle triangle (with the Pythagorean Theorem):

AB=\sqrt{15^2+20^2} =\sqrt{625} =25

Now, to get a 2:3 proportion on Segment AB which is of length 25, we need to divide it in five equal parts (see the picture on the right of the attached image), and place point M at two of these divisions from point A (0,15) and along segment AB.

In order to find the appropriate location in (x,y) coordinates, we consider a smaller triangle (pictured in orange in the image) that is similar to the first larger triangle (pictured in blue). Notice that if the length of AB is 25,  each of its five equal divisions would be of length "5", and therefore two of them will render a length of "10" (which is the hypotenuse of this smaller right angle triangle.

Now, in order to find the sides of this smaller triangle (which can give us the clues on the horizontal and vertical coordinates of point M), we can use proportions.

To find the length "x" of the horizontal side , we do:

\frac{x}{10} =\frac{20}{25} \\x=\frac{10*20}{25} \\x=8

To find the length "y" of the vertical side , we do:

\frac{y}{10} =\frac{15}{25} \\y=\frac{10*15}{25} \\y=6

Then, the coordinate "x" of point M will be "8", while we can calculate the y position of point M subtracting "6" from 15 (the length of the vertical side in the original triangle). This gives us the coordinates (8,9) for point M as marked in orange in the picture.

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What is the total surface area of the square pyramid
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