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Reil [10]
3 years ago
6

HELP THIS IS DUE AT 12

Mathematics
2 answers:
kap26 [50]3 years ago
7 0

Answer:

16

Step-by-step explanation:

4×.75=3

8×.75=6

16×.75=12

20×.75=15

Free_Kalibri [48]3 years ago
7 0

Answer:

whaa its the same type of question... 16...

Step-by-step explanation:

again, what grade are you in smh

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YES I WILL MARK BRAINLIST !!! Algebra please help me with these Im timed!!!!!!!!
Phoenix [80]

Answer:

The answer is the last one: One runner in the study runs 31...

Step-by-step explanation:

31 is the input (x) and 81 is the output (y) and since there's 1 ordered pair per runner, it's going to be one runner, and the input is the miles ran.

5 0
3 years ago
Read 2 more answers
I don't understand this, please help ​
dimulka [17.4K]

Answer:

∠2 = 150°, it is a supplementary angle to 30°

∠3 = 30°, it is an alternate angle to 30°

∠4 = 150°, it is a supplementary angle to 30°

∠5 = 30°, it is an alternate angle to 30°

∠6 = 150°, it is a supplementary angle to 30°

∠7 = 30°, it is an alternate angle to 30°

∠8 = 150°, it is a supplementary angle to 30°

6 0
3 years ago
The four angles of a quadrilateral are in the ratio 2:3:5:8. Find the angles
sp2606 [1]

Answer:

Step-by-step explanation: let 2:3:5:8 be 2x,3x,5x,8x respectively .

*angles in a quadrilateral is 360 degree

*2x+3x+5x+8x=360

*18x=360

*x=360/18

*x=20

now substitute x in these:

2x=2x20=40

3x=3x20=60

5x=5x20=100

8x=8x20= 160

so these are the following angles: 40,60,100 and 160

8 0
3 years ago
Find all the real square roots of 0.0036
amm1812
The square root of 0.0036 can be calculated through the calculator. The answer is 0.06. WE can also take by the eye the square root of 0.0036 in which the square root of 36 is 6. The number must be greater than 0.0036. The answer is 0.06.
7 0
3 years ago
Find the tenth term of the expansion (x+ y)¹³
Anon25 [30]

Answer:

715x^4y^9

Step-by-step explanation:

Given

(x + y)^{13

Required

Determine the 10th term

Using binomial expansion, we have:

(a + b)^n = ^nC_0a^nb^0 + ^nC_1a^{n-1}b^1 + ^nC_2a^{n-2}b^2 +.....+^nC_na^{0}b^n

For, the 10th term. n = 9

So, we have:

(a + b)^n = ^nC_{9}a^{n-9}b^{9

(x + y)^{13} = ^{13}C_{9}x^{13-9}y^9

(x + y)^{13} = ^{13}C_{9}x^4y^9

Apply combination formula

(x + y)^{13} = \frac{13!}{(13-9)!9!}x^4y^9

(x + y)^{13} = \frac{13!}{4!9!}x^4y^9

(x + y)^{13} = \frac{13*12*11*10*9!}{4!9!}x^4y^9

(x + y)^{13} = \frac{13*12*11*10}{4!}x^4y^9

(x + y)^{13} = \frac{13*12*11*10}{4*3*2*1}x^4y^9

(x + y)^{13} = \frac{17160}{24}x^4y^9

(x + y)^{13} = 715x^4y^9

Hence, the 10th term is 715x^4y^9

3 0
3 years ago
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