All categories

2 years ago

What is the range of F(x) = -4cos2x?

Mathematics

1 answer:

MArishka [77]2 years ago

3 0

Assuming you want the range of
-4cos(2x)

the range of the cosine function is -1 to 1. When that is scaled by a factor of -4, it becomes 4 to -4.

The range of F(x) is [-4, 4] in interval notation.

_____
If you want the range of
F(x) = -4cos²(x)
that range will be -4×[0, 1] = [-4, 0].

You might be interested in

1/6 divided by 6 by 6

Ahat [919]

the answer is 1/216

hope this might of helped :/

7 0

2 years ago

Read 2 more answers

A train travels train travels 288 kilometre at a uniform speed. If the speed had been 4 kilometre per hour more it would have ta

kiruha [24]

Answer:

Let the speed of the train be x km/h.

Case 1:

Distance = 288 km

Speed = x km/h

Time = Distance/Speed

= 288/x h

Case 2:

Distance = 288 km

Speed = (x+4) km/h

Time = 288/x + 4 h

Since 288/x > 288/x + 4

288/x - 288/x+4 = 1

288[1/x - 1/x+4 ] = 1

[ x + 4 - x / x(x + 4) ] = 1/288

[4 / x^2 + 4x ] = 1/288

x^2 + 4x = 1152

x^2 + 4x - 1152 = 0

x^2 + 36x - 32x - 1152 = 0

x(x + 36) - 32(x + 36) = 0

(x + 36)(x - 32) = 0

x + 36 = 0 , x - 32 = 0

x = -36 , x = 32

x = -36 , rejected since speed cannot be negative.

Therefore , speed of the train = 32 km/h

4 0

2 years ago

This is a problem I really need help on please help so I actually have two lol put please help with 7 and 8

grigory [225]

Answer:

f(n) = 80*3^n

f(n) = 4 * 3^(n - 1)

7 0

2 years ago

PLEASE HELPPPPP!!!!!!!!! (show work if you can)

Kryger [21]

Answer:

$180x^4y^3z^2$

Step-by-step explanation:

Start by finding the LCM of the coefficients of each polynomial:

$LCM(12,18,30)=180$

Next, to find the least common multiple of each of the following terms, we need to take the absolute minimum we can of each term ( $x$ , $y$ , and $z$ ). The largest term of $x$ is $x^4$ in the first polynomial, so we'll take exactly that for our $x$ term in the LCM, absolutely nothing more. Similarly, the largest term of $y$ in any of the three polynomials is $y^3$ (also in the first polynomial) and the largest $z$ term in any of the three polynomials is $z^2$ in the second polynomial. Thus, the LCM of all our polynomials is: