Solve the area of the whole circle since in an hour, the minute hand covers the whole clock
assuming that the minute hand reaches all the way out to the edge of the clock
the minute hand is the radius
area=pi times r^2
r=5
5^2=25
area=pi times 25
area=25pi
aprox pi=3.14
25 times 2.14=78.5
area=78.5 in^2
Answer:
Two angles and the non-included side of one triangle are congruent to the corresponding parts of another triangle. Which congruence theorem can be used to prove that the triangles are congruent? Two sides and the included angle of one triangle are congruent to the corresponding parts of another triangle.
Answer: False
Step-by-step explanation:
Hope this helps
<h3>
Answer: Choice B</h3><h3>
y = x^2 + 7x + 1</h3>
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Proof:
A quick way to confirm that choice B is the only answer is to eliminate the other non-answers.
If you plugged x = 1 into the equation for choice A, you would get
y = -x^2 + 7x + 1
y = -1^2 + 7(1) + 1
y = -1 + 7 + 1
y = 7
We get a result of 7, but we want 9 to be the actual output. So choice A is out.
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Repeat for choice C. Plug in x = 1
y = x^2 - 7x + 1
y = 1^2 - 7(1) + 1
y = 1 - 7 + 1
y = -5
We can eliminate choice C (since again we want a result of y = 9)
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Finally let's check choice D
y = x^2 - 7x - 1
y = 1^2 - 7(1) - 1
y = 1 - 7 - 1
y= -7
so choice D is off the list as well
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The only thing left is choice B, so it must be the answer. It turns out that plugging x = 1 into this equation leads to y = 9 as shown below
y = x^2 + 7x + 1
y = 1^2 + 7(1) + 1
y = 1 + 7 + 1
y = 9
And the same applies to any other x value in the table (eg: plugging in x = 3 leads to y = 31, etc etc).
