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Ksenya-84 [330]
3 years ago
15

Ricardo spends 2 2/3 hours practicing soccer on

Mathematics
1 answer:
ladessa [460]3 years ago
3 0

Answer:

10 7/12 hours

Step-by-step explanation:

so we have to multiply 2 2/3 twice since he does that many hours for 2 days. We then have to multiply 1 3/4 three times since he does that many hours for 3 days. Lets first convert 2 2/3 into a mixed fraction. 2 2/3 = 3 times 2 =6 +2=8 over 3. 1 3/4=4 times 1=4+3=7 over 4. 8/3 times 2 equals 16/3 which eqials

5 1/3 hours. 7/4 times 3 equals to 21/4 which equals to 5 1/4. Lets now add

5 1/3 and 5 1/4. 5+5=10 but the fractions are not the same. Therefore, we need to make it to a common denominator. 4 times 3 equals to 12 so 4/12 plus 3/12 equals 7/12. Final answer equals to 10 7/12.

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Samantha reports that 60% of the first year students at her university think they should be able to bring a car to campus. She a
Nostrana [21]

Answer:

D) the standard error for her sample is 15

Step-by-step explanation:

Samantha is 95% certain that between 50% and 70% of the first year students agree that they should be able to bring a car to campus.

Here

  • 95% is the confidence level.
  • The range between 50% and 70% indicates 95% confidence interval.
  • 60% is the average proportion of the first year students at her university think they should be able to bring a car to campus.
  • 10% (0.1) is the margin of error from the mean

Since standard error can be obtained by dividing margin of error by the z-statistic of the confidence level which is 1.96. The standard error for her sample \frac{0.1}{1.96} does not equal to 15.

4 0
3 years ago
PLEASE HELP!!!!! HAVING TROUBLE <br><br> (see attached images)
qaws [65]

Answer:

The Proof for

Part C , Qs 9 and Qs 10  is below.

Step-by-step explanation:

PART C .

Given:

AD || BC ,

AE ≅ EC

To Prove:

ΔAED ≅ ΔCEB

Proof:

Statement                             Reason

1. AD || BC                           1. Given

2. ∠A ≅ ∠C                        2. Alternate Angles Theorem as AD || BC

3. ∠AED ≅ ∠CEB               3. Vertical Opposite Angle Theorem.

4. AE ≅ EC                        4. Given

5. ΔAED ≅ ΔCEB              5. By A-S-A congruence test....Proved

Qs 9)

Given:

AB ≅ BC ,

∠ABD ≅ ∠CBD

To Prove:

∠A ≅ ∠C

Proof:

Statement                             Reason

1. AB ≅ BC                        1. Given

2. ∠ABD ≅ ∠CBD            2. Given      

3. BD ≅ BD                       3. Reflexive Property

4. ΔABD ≅ ΔCBD             4. By S-A-S congruence test

5. ∠A ≅ ∠C                       5. Corresponding parts of congruent Triangles Proved.

Qs 10)

Given:

∠MCI ≅ ∠AIC

MC ≅ AI

To Prove:

ΔMCI ≅ ΔAIC

Proof:

Statement                             Reason

1. ∠MCI ≅ ∠AIC       1. Given

2. MC ≅ AI              2. Given

3. CI ≅ CI                3. Reflexive Property

4. ΔMCI ≅ ΔAIC     4. By S-A-S congruence test

4 0
3 years ago
(2x^2+4x+3) - (4x^2 -2x-3)
ankoles [38]

Answer:

x^{2}+6x+6 is your answer

7 0
2 years ago
Read 2 more answers
If a polynomial function f(x) has roots 3+
irinina [24]

Answer:

Step-by-step explanation:

3+√5 is a root.

so 3-√5 is also a root

or (x-(3-√5)) is also a factor of f(x)

7 0
2 years ago
Suppose a teacher gives 10 points for putting your name on a 100 point test. The minimum score on that test is 10 and the maximu
Varvara68 [4.7K]
I think it is x+10=>100
8 0
3 years ago
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