Ricardo spends 2 2/3 hours practicing soccer on

Mathematics

1 answer:

ladessa [460]3 years ago

3 0

Answer:

10 7/12 hours

Step-by-step explanation:

so we have to multiply 2 2/3 twice since he does that many hours for 2 days. We then have to multiply 1 3/4 three times since he does that many hours for 3 days. Lets first convert 2 2/3 into a mixed fraction. 2 2/3 = 3 times 2 =6 +2=8 over 3. 1 3/4=4 times 1=4+3=7 over 4. 8/3 times 2 equals 16/3 which eqials

5 1/3 hours. 7/4 times 3 equals to 21/4 which equals to 5 1/4. Lets now add

5 1/3 and 5 1/4. 5+5=10 but the fractions are not the same. Therefore, we need to make it to a common denominator. 4 times 3 equals to 12 so 4/12 plus 3/12 equals 7/12. Final answer equals to 10 7/12.

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3.84761 to 3 decimal place

yKpoI14uk [10]

The answer is 3.848.

3 0

2 years ago

If you are offered one slice from a round pizza (in other words, a sector of a circle) and the slice must have a perimeter of 24

VARVARA [1.3K]

Answer:

A 12 in diameter will reward you with the largest slice of pizza.

Step-by-step explanation:

Let $r$ be the radius and $\theta$ be the angle of a circle.

According with the graph, the area of the sector is given by

$A=\frac{1}{2}r^2\theta$

The arc lenght of a circle with radius $r$ and angle $\theta$ is $r \theta$

The perimeter of the pizza slice is composed of two straight pieces, each of length r inches, and an arc of the circle which you know has length s = rθ inches. Thus the perimeter has length

$2r+r\theta=24 \:in$

We need to express the area as a function of one variable, to do this we use the above equation and we solve for $\theta$

$2r+r\theta=24\\r\theta=24-2r\\\theta=\frac{24-2r}{r}$

Next, we substitute this equation into the area equation

$A=\frac{1}{2}r^2(\frac{24-2r}{r})\\A=\frac{1}{2}r(24-2r)\\A=12r-r^2$

The domain of the area is

$0$

To find the diameter of pizza that will reward you with the largest slice you need to find the derivative of the area and set it equal to zero to find the critical points.

$\frac{d}{dr} A=\frac{d}{dr}(12r-r^2)\\A'(r)=\frac{d}{dr}(12r)-\frac{d}{dr}(r^2)\\A'(r)=12-2r$