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UNO [17]
2 years ago
10

At what rates did she invest? $1500 invested at___% $800 invested at ____%

Mathematics
1 answer:
frosja888 [35]2 years ago
3 0

Answer:

4% and 5% respectively

Step-by-step explanation:

Let the intrest rate be x in the first account at x% and (x+1)% in the second account.

ATQ, 100=(x)*1500/100+(x+1)*800/100

x=4.

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Write an expression that is equivalent to -2/5(15 - 20d +50)<br> Explain please!:)
valina [46]

Answer:

-26 + 4/5d

Step-by-step explanation:

-2/5 ( 15 - 2d + 50)

= -2/5 ( 65 - 2d)

= -2/5 * 65 - (-2/5) * 2d

= -26 - (-4/5d)

= -26 + 4/5d

3 0
2 years ago
Just answer # 1 please
Rudiy27
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4 0
3 years ago
Please see attachment!!! The formula for finding the area of a rectangle is
pychu [463]

Answer:

36cm^2

Step-by-step explanation:

4cm×9cm=36cm^2

5 0
3 years ago
Read 2 more answers
Please Help.
Gennadij [26K]
Answer:
amount of nuts = 2 pounds
amount of dried fruit = 4 pounds

Explanation:
We are given that x is the amount of nuts and y is the amount of dried fruit.
We are also given that:
1- Hunter needs to make 6 pounds of trail mix. This means that:
x + y = 6
This can be rewritten as:
x = 6 - y .........> equation I
2- x costs $4 per pound, y costs $3.5 and Hunter can spend a total of $22. This means that:
4x + 3.5y = 22 ..........> equation II

Substitute with equation I in equation II and solve for y as follows:
4x + 3.5y = 22
4(6-y) + 3.5y = 22
24 - 4y + 3.5y = 22
24-22 = 4y-3.5y
2 = 0.5y
y = 4 pounds

Substitute with y in equation I to get the value of x as follows:
x = 6-y
x = 6-4
x = 2 pounds

Hope this helps :)

7 0
3 years ago
If the producer in a food chain has 1000 kcal of energy available, how much energy would each of the consumers have?
madam [21]

Answer:

Primary consumer = 100kcal

Secondary consumer = 10kcal

Tertiary consumer = 1kcal

Step-by-step explanation:

In a food chain, transfer of energy occurs when one organism feeds on another organism. However, only 10% of energy is transferred from one organism to another because energy is lost as heat when the organisms perform metabolism.

In a typical food chain consisting of a producer, a primary (1st), secondary (2nd) and tertiary (3rd) consumer, if there are 1000 kcal of energy available in the producer, then:

- Primary consumer will obtain; 10% of 1000Kcal

10/100 × 1000

Primary consumer = 100kcal of energy.

- Secondary consumer will obtain as follows; 10% of 100kcal available energy

= 10/100 × 100

Secondary consumer = 10Kcal of energy.

- Tertiary consumer will obtain as follows; 10% of 10Kcal of available energy.

= 10/100 × 10

Tertiary consumer = 1 kcal of energy.

6 0
3 years ago
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