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UNO [17]
3 years ago
10

At what rates did she invest? $1500 invested at___% $800 invested at ____%

Mathematics
1 answer:
frosja888 [35]3 years ago
3 0

Answer:

4% and 5% respectively

Step-by-step explanation:

Let the intrest rate be x in the first account at x% and (x+1)% in the second account.

ATQ, 100=(x)*1500/100+(x+1)*800/100

x=4.

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What is the answer? Thank you
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In the study of a nonlinear spring with periodic​ forcing, the equation y prime prime plus ky plus ry cubedy′′+ky+ry3equals=Uppe
Ymorist [56]

Answer:

\mathbf{y(t) = t + \dfrac{7}{2}t^2 - \dfrac{2}{3}t^3+ ...}

Step-by-step explanation:

THe interpretation of the given question is as follows:

y'' + ky +  ry³ = A cos ωt

Let k = 4, r = 3, A = 7 and ω = 8

The objective is to find the first three non zero terms in the Taylor polynomial approximation to the solution with initial values y(0) = 0 ; y' (0) = 1

SO;

y'' + ky " ry³ = A cos ωt

where;

k = 4, r = 3, A = 7 and ω = 8

y(0) = 0 ; y' (0) = 1

y'' + 4y + 3y³ = 7 cos 8t

y'' = - 4y - 3y³ + 7 cos 8t     ---- (1)

∴

y'' (0) = -4y(0) - 3y³(0) + 7 cos (0)

y'' (0) = - 4 × 0 - 3 × 0 + 7

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Differentiating equation (1) with respect to  t ; we have:

y''' = - 4y' - 9y² × y¹ - 56 sin 8t

y''' (0) = -4y'(0) - 9y²(0)× y¹ (0) - 56 sin (0)

y''' (0) = - 4 × 1  - 9 × 0 × 1 - 56 × 0

y''' (0) = - 4

Thus; we have :

y(0) = 0  ; y'(0) = 1  ; y'' (0) = 7 ; y'''(0) = -4

Therefore; the Taylor polynomial approximation to the first three nonzero terms is :

y(t) = y(0) + y'(0) t + y''(0) \dfrac{t^2}{2!} + y'''(0) \dfrac{t^3}{3!}+...

y(t) = 0 +  t + 7 \dfrac{t^2}{2!} + \dfrac{-4}{3!} {t^3}+ ...

\mathbf{y(t) = t + \dfrac{7}{2}t^2 - \dfrac{2}{3}t^3+ ...}

6 0
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bezimeni [28]
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Answer:

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