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2 years ago

At what rates did she invest? $1500 invested at_% $800 invested at __%

Mathematics

1 answer:

frosja888 [35]2 years ago

3 0

Answer:

4% and 5% respectively

Step-by-step explanation:

Let the intrest rate be x in the first account at x% and (x+1)% in the second account.

ATQ, 100=(x)*1500/100+(x+1)*800/100

x=4.

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What is the value of x

Goshia [24]

Sum of all adjacent angles is 180°.

3x + 12 + x = 180
4x + 12 = 180
4x = 168
x = 42°

-----------------------------------------
Answer: x = 42°
-----------------------------------------

3 0

3 years ago

What are the coordinates of the endpoints of the mid segment of triangle ABC that is parallel to line AB?

MrMuchimi

Answer:

$(4.5,4)$ and $(4.5,6.5)$

Step-by-step explanation:

we have the coordinates

A(2,7),B(2,2),C(7,6)

we know that

The mid segment of triangle ABC that is parallel to line AB is located between the mid point AC and the mid point BC

The formula to calculate the midpoint between two points is equal to

$(\frac{x1+x2}{2},\frac{y1+y2}{2})$

step 1

Find the mid point AC

we have

A(2,7),C(7,6)

substitute in the formula

$(\frac{2+7}{2},\frac{7+6}{2})$

$(4.5,6.5)$

step 2

Find the mid point BC

we have

B(2,2),C(7,6)

substitute in the formula

$(\frac{2+7}{2},\frac{2+6}{2})$

$(4.5,4)$

therefore

The endpoints of the mid segment of triangle ABC that is parallel to line AB are $(4.5,4)$ and $(4.5,6.5)$

8 0

3 years ago

A boat can travel at an average speed of 10 miles per hour in still water. Traveling with the current, it can travel 6 miles in

oksano4ka [1.4K]

Answer: The speed of the current is 2 miles per hour.

Step-by-step explanation:

We know that the speed of the boat is:

S = 10 mph.

When the boat travels with the current, the speed will be:

S = 10mph + x

where x = speed of the current.

When the boat travels against the current, the speed will be:

S = 10mph - x

Now, for a given amount of time T, when the boat travels with the current, it moves a distance of 6 miles.

Then we have the equation:

(10mph + x)*T = 6mi

And against the current, in the same time the boat moves 4 mi, then:

(10 mph - x)*T = 4mi

Then we have the system of equations:

(10mph + x)*T = 6mi

(10 mph - x)*T = 4mi

Now, we can take the quotient of these two equations and get:

((10mph + x)*T)/((10 mph - x)*T) = (6mi/4mi)

(10mph + x)/(10 mph - x) = 3/2

Now we can solve this for x.

(10mph + x) = (3/2)*(10 mph - x)

10mph + x = (3/2)*10mph - (3/2)*x

x + (3/2)*x = (3/2)*10mph - 10mph

(5/2)*x = (1/2)*10mph = 5mph

x = (2/5)*5mph = 2mph.

The speed of the current is 2 miles per hour.

6 0

3 years ago

Read 2 more answers

-3x+4>-23 what is the answer I need help

Dmitrij [34]

X<9
The answer is x<9 because you first subtract 4 from both sides then divide both sides by -3. Which then would give you 9.

5 0

3 years ago

Which piece of additional information can be used to prove △CEA ~ △CDB?

8_murik_8 [283]

<h3>Answer:</h3>

∠BDC and ∠AED are right angles

<h3>Step-by-step explanation:</h3>

Because ∠C ≅ ∠C, the additional bit of information above can be used to show AA similarity.

____

None of the other offered choices says anything about <em>both</em> triangles. In order to show similarity, you need information about corresponding parts of the <em>two</em> triangles. Information about one triangle alone is not sufficient.

5 0

3 years ago

At what rates did she invest? $1500 invested at___% $800 invested at ____%

At what rates did she invest? $1500 invested at_% $800 invested at __%