Answer:
550
Step-by-step explanation:
We aren't given that they are consecutive so lets just pretend the numbers are x, y, z , and r.
We are given x+y+z+r=1320
We are also given that y+z+r=.4x+x
Simplifying my second equation gives us y+z+r=1.4x. I'm going to plug this into first equation giving me
x+1.4x=1320
2.4x=1320
So x=1320/2.4=550
33+9= 42+12= 54+2=90-56= 34 34+3x
I don't know
answer ...
to halp you and thank you
Answer:
(1/2,4)
Step-by-step explanation:
First, determine y in first equation: 2x+y=5 or y=5-2x
replace value of y determined in first equation (5-2x) into 2nd equation
4x-3(5-2x)=-10
4x-15+6x=10
10x=5
x=1/2
put value of x into either equation to solve for y so
2(1/2)+y=5
1+y=5
y=4
answer: x=1/2, y=4
check answer by substituting x and y into either equation:
4x-3y=-10
4(1/2)-3(4)=-10
2-12=-10
-10=-10
or
2x+y=5
2(1/2)+4=5
1+4=5
5=5
(a+b)(a-b)=a^2 - b^2
so
<span>(4x-7)(4x+7) = 16x^2 - 49
answer
</span>16x^2 - 49
