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Scrat [10]
3 years ago
9

The parent function f(x) = 1.5x is translated such that the function g(x) = 1.5x + 1 + 2 represents the new function. Which is t

he graph of g(x)?
Mathematics
2 answers:
Nikitich [7]3 years ago
8 0

Answer:

Graph of f(x) is shifted up by 3 unit .

Step-by-step explanation:

Given : The parent function f(x) = 1.5x is translated such that the function g(x) = 1.5x + 1 + 2 .

To find : Which is the graph of g(x).

Solution : We have given that parent function f(x) = 1.5x.

Transformed function g(x) = 1.5x + 1 + 2 .

By the transformation rule f(x) + k it means graph of f(x) shifted  up by k unit .

So, g(x) = 1.5x +3 .

Therefore. Graph of f(x) is shifted up by 3 unit .

Gennadij [26K]3 years ago
6 0

graph of g is the the graph of f shifted 3 units above

i dont know if the translator translate that coreclty

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Calculate S58 for the arithmetic sequence {an}= {5/6n+1/3} If you could show me the steps that would be great. I keep following
Amanda [17]

Answer is 8671/6 which is the third choice

===================================

Work Shown:

Find the first term of the sequence by plugging in n = 1

a_n = (5/6)*n + 1/3

a_1 = (5/6)*1 + 1/3    replace n with 1

a_1 = 5/6 + 1/3

a_1 = 5/6 + 2/6

a_1 = 7/6

Repeat for n = 58 to get the 58th term

a_n = (5/6)*n + 1/3

a_58 = (5/6)*58 + 1/3    replace n with 58

a_58 = (5/6)*(58/1) + 1/3

a_58 = (5*58)/(6*1) + 1/3

a_58 = 290/6 + 1/3

a_58 = 145/3 + 1/3

a_58 = 146/3

Now we can use the s_n formula below with n = 58

s_n = (n/2)*(a_1 + a_n)

s_58 = (58/2)*(a_1 + a_58)    replace n with 58

s_58 = (58/2)*(7/6 + a_58)   replace a_1 with 7/6

s_58 = (58/2)*(7/6 + 146/3)   replace a_58 with 146/3

s_58 = (58/2)*(7/6 + 292/6)

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s_58 = (58*299)/(2*6)

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3 years ago
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To solve an equation or inequality, you can add the same value to both sides of the expression. Here, it is convenient to choose that value to be the opposite of the constant (+15) added to y, so that constant is replaced by zero.


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  y < -12 . . . . . . . . . . . . . . . the result of simplifying. This is your solution.

6 0
3 years ago
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