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BaLLatris [955]
3 years ago
9

Multiply. (w-7) (w+4)

Mathematics
1 answer:
stira [4]3 years ago
5 0

Use the FOIL (first, outside, inside, last) to expand the terms in the brackets.

(w - 7)(w + 4)

first: w × w = w²

outside: w × 4 = 4w

inside: -7 × w = -7w

last: -7 × 4 = -28

Now you add all the terms together to get:

w² + 4w - 7w - 28

This simplifies to give you:

w² - 3w - 28

Hope that helps! :)

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This table gives a few (x,y) pairs of a line in the coordinate plane
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Answer:

-41

Step-by-step explanation:

Use 2 points to find the equation of the line using the 2-point form of the equation of a line. Then we write the equation in the slope-intercept form to find the y-intercept.

y - y_1 = \dfrac{y_2 - y_1}{x_2 - x_1}(x - x_1)

We can use points (-36, -117) and (-27, -98), so

x1 = -36

x2 = -27

y1 = -117

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y - (-117) = \dfrac{-98 - (-117)}{-27 - (-36)}(x - (-36))

y + 117 = \dfrac{19}{9}(x + 36)

y + 117 = \dfrac{19}{9}x + 76

y = \dfrac{19}{9}x - 41

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4 0
4 years ago
A clerk at Agency Y has determined that at speeds of 25 pages per minute it is typical for 3 out of every 100 pages she photocop
nalin [4]

Answer:

180 pages

Step-by-step explanation:

Since her photocopy session is 25 pages per minute, the total number of pages photocopied in 4 hour session can be calculated as;

number of pages = time × speed

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Thus, number of pages photocopied in 4 hours is 6000.

For every 100 pages, 3 would contain some type of printing error. The number of pages she expect with printing error during 4 hour session can be determined as;

           = \frac{6000}{100} × 3

           = 60 × 3

           = 180 pages

The expected number of pages with printing error during 4 hour photocopying session is 180 pages.

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3 years ago
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Answer:

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Answer:
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