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Dovator [93]
3 years ago
10

Angle A and B are complementary What is the value of x?

Mathematics
2 answers:
const2013 [10]3 years ago
7 0

Answer:

x=34

Step-by-step explanation:

put in equation

x+x+22=90 degrees

2x+22=90

2x=68

x=34

ANTONII [103]3 years ago
3 0
<h3>Answer: x = 34</h3>

=======================================================

Explanation:

A+B = 90 ... complementary angles add to 90 degrees

(x+22) + (x) = 90

x+22+x = 90

2x+22 = 90

2x = 90-22 ... subtract 22 from both sides

2x = 68

x = 68/2 ... divide both sides by 2

x = 34

--------------------

Extra info:

if x = 34, then angle A is x+22 = 34+22 = 56 degrees

Then we can see that A+B = 56+34 = 90, which confirms our answer

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An airplane makes a 400-mile trip against a head wind in 4 hours. The return trip takes 2.5 hours, the wind now being a tall win
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Answer:

v_p=130\ miles/h

v_w=30\ miles/h

Step-by-step explanation:

Lets call v_p the the still-air speed of the plane and v_w the speed of the wind. On the first part the speed of the plane relative to the ground will be v_1=v_p-v_w, and on the second part it will be v_2=v_p+v_w.

We know that the distance d=400 miles on the first and second parts are the same, so by the definition of velocity we will have:

v_1=\frac{d}{t1}

v_2=\frac{d}{t2}

Or:

v_p-v_w=\frac{d}{t1}

v_p+v_w=\frac{d}{t2}

Adding both equations:

(v_p-v_w)+(v_p+v_w)=2v_p=\frac{d}{t1}+\frac{d}{t2}

v_p=\frac{1}{2}(\frac{d}{t1}+\frac{d}{t2})

Which for our values is:

v_p=\frac{1}{2}(\frac{400\ miles}{4h}+\frac{400\ miles}{2.5h})=130\ miles/h

If instead of adding, we substact, we would have:

(v_p+v_w)-(v_p-v_w)=2v_w=\frac{d}{t2}-\frac{d}{t1}

v_w=\frac{1}{2}(\frac{d}{t2}-\frac{d}{t1})

Which for our values is:

v_w=\frac{1}{2}(\frac{400\ miles}{2.5h}-\frac{400\ miles}{4h})=30\ miles/h

6 0
4 years ago
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