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anzhelika [568]

3 years ago

6

In a right triangle the length of a hypotenuse is c and the length of one leg is a, and the length of the other leg is b, what i

s the value of b, if
c=13, a=12?

1 answer:

mart [117]3 years ago

5 0

Answer:

5

Step-by-step explanation:

Square of 13 minus square of 12 and then under root.. You will get 5

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Charra [1.4K]

Answer:

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Step-by-step explanation:

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4 0

2 years ago

Read 2 more answers

HELPP!!! 65 points GIVIN

WITCHER [35]

its 3 1/4 you will thank me later :)

5 0

2 years ago

Can anyone help me with inverse function please?

12345 [234]

${h}^{ - 1} oh(x) = x \\ {h}^{ - 1} (4x + m) = x \\ 2k(4x + m) + \frac{5}{8} = x \\ 8kx + 2km + \frac{5}{8} = x$

k and m must satisfy 8k = 1 mean k = ⅛

and 2km+⅝=0 mean m = -5/2

4 0

3 years ago

Which polynomial correctly combines the like terms and puts the given polynomial in standard form? -5x^3y^3+8x^4y^2-xy^5-2x^2y^4

victus00 [196]

Given:

The polynomial is:

$-5x^3y^3+8x^4y^2-xy^5-2x^2y^4+8x^6+3x^2y^4-6xy^5$

To find:

The simplified form of the given polynomial in standard form.

Solution:

We have,

$-5x^3y^3+8x^4y^2-xy^5-2x^2y^4+8x^6+3x^2y^4-6xy^5$

Combining the like terms, we get

$=-5x^3y^3+8x^4y^2+(-2x^2y^4+3x^2y^4)+8x^6+(-xy^5-6xy^5)$

$=-5x^3y^3+8x^4y^2+x^2y^4+8x^6-7xy^5$

Now, rewrite this polynomial in standard form.

$=8x^6+8x^4y^2-5x^3y^3+x^2y^4-7xy^5$

Therefore, the required polynomial in standard form is $8x^6+8x^4y^2-5x^3y^3+x^2y^4-7xy^5$ .

8 0

3 years ago

Translation: 6 units down s(-4,1), 7(-3, 5), (0,2 )

tia_tia [17]

(-4,-5) (-3,-1) (0,-4)

4 0

2 years ago