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4 years ago

Problem 48, need help

Mathematics

1 answer:

My name is Ann [436]4 years ago

8 0

Im not sure but im guessing 46?

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Determine which is bigger a 8.5 by 12 rectangulae pizza or a circular 12 pizza

kotegsom [21]

Answer:

circular pizza

Step-by-step explanation

rectangular - 8.5 x 12= 102

circular - 12 x 12= 144

6 0

3 years ago

The perimeter of a rectangle is 84. If the length is 2 more than three times the width, what are the dimensions of the rectangle

Marina86 [1]

The perimeter solved shows that the dimensions of the rectangle are 32 and 10.

<h3>How to calculate the perimeter</h3>

Let the width be w

Length = 3w + 2

Perimeter = 2(length + width)

Perimeter = 2(3w + 2) + 2w

6w + 4 + 2w = 84

8w + 4 = 84

8w = 84 - 4

w = 80/8

w = 10

Length = 3w + 2

Length = 3(10) + 2

Length = 32

The dimensions of the rectangle are 32 and 10.

Learn more about perimeter on:

brainly.com/question/19819849

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2 years ago

Multiply.<br><br> [−427⋅(−18)]⋅(−389)⋅(−1)<br><br> What is the product?

Alex_Xolod [135]

The final product would be 2989854

8 0

3 years ago

Read 2 more answers

Which of the following is an integer?<br> 0.5<br> 1<br> 3/2

Vinil7 [7]

Yeah the answer is one

3 0

3 years ago

Read 2 more answers

Drag each tile to the correct box consider the given functions f,g and h place the tiles in order from least to greatest accordi

Alja [10]

Answer:

Step-by-step explanation:

By definition, the average rate of change of a function f over an interval [a,b] is given by

$\dfrac{f(b)-f(a)}{b-a}$

compute the quantity

$\dfrac{f(3)-f(0)}{3}$

for all the three function

Average rate of change of f:

We will simply use the table to check the values for f(3) and f(0):

$\dfrac{f(3)-f(0)}{3}=\dfrac{10-1}{3} = 3$

Average rate of change of g:

We will use the graph to to check the values for g(3) and g(0):

$\dfrac{g(3)-g(0)}{3}=\dfrac{8-1}{3} = \dfrac{7}{3}$

Average rate of change of h:

We can plug the values in the equation to get h(3) and h(0):

$h(3)=3^2+3-6=9+3-6=6,\quad h(0)=0^2+0-6=-6$

And so the average rate of change is

$\dfrac{h(3)-h(0)}{3}=\dfrac{6-(-6)}{3} = 4$

3 0

4 years ago