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BaLLatris [955]
3 years ago
15

Which choice is equivalent to the expression below?

Mathematics
2 answers:
alekssr [168]3 years ago
6 0

Answer: OPTION A

Step-by-step explanation:

We need to remember that Product of powers property, which states that:

(a^m)(a^n)=a^{(m+n)}

Let's check the options:

A. For 5^9*5^{\frac{9}{10}}*5^{\frac{6}{100}}*5^{\frac{9}{1000}} you can  apply the property mentioned before. Then:

5^{(9+\frac{9}{10}+\frac{6}{100}+\frac{9}{1000})=5^{9.969}

(It is the equivalent expression)

 B. Add the exponents:

 5^9*5^{(\frac{9}{10}+\frac{9}{10}+\frac{6}{1000})=5^{10.806}

(It is not the equivalent expression)

C. For 5^9*5^{\frac{96}{10}}*5^{\frac{9}{100}}} you can  apply the property mentioned before. Then:

 5^{(9+\frac{96}{10}+\frac{9}{100})=5^{18.69}

(It is not the equivalent expression)

D. We know that 5^{9.969}=9,290,347.808 and we maje the addition indicated in this option, we get:

 5^9+5^{\frac{9}{10}}+6^{\frac{6}{100}}=1,953,130.37

(It is not the equivalent expression)

raketka [301]3 years ago
6 0

Answer: A, i just took this test

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An airplane covers 94 miles in 1/6 of an hour. How many miles the plane can cover in 6 hours?
jeyben [28]

Let's find what 1/6 of an hour is.

1/6×60=10

So, ten minutes is equal to 1/6 of an hour. Let's find hour many sets of 10 minutes are in six hours. Let's first find the amount of minutes.

6×60=360

360÷10

36

Let's multiply that by 94.

94×36

3,384 miles in 6 hours.

7 0
3 years ago
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Can someone help me do part two please? It’s very important send a picture or something. I don’t even care if you tell me the st
Nataly_w [17]
<h3>Explanation:</h3>

1. "Create your own circle on a complex plane."

The equation of a circle in the complex plane can be written a number of ways. For center c (a complex number) and radius r (a positive real number), one formula is ...

  |z-c| = r

If we let c = 2+i and r = 5, the equation becomes ...

  |z -(2+i)| = 5

For z = x + yi and |z| = √(x² +y²), this equation is equivalent to the Cartesian coordinate equation ...

  (x -2)² +(y -1)² = 5²

__

2. "Choose two end points of a diameter to prove the diameter and radius of the circle."

We don't know what "prove the diameter and radius" means. We can show that the chosen end points z₁ and z₂ are 10 units apart, and their midpoint is the center of the circle c.

For the end points of a diameter, we choose ...

  • z₁ = 5 +5i
  • z₂ = -1 -3i

The distance between these is ...

  |z₂ -z₁| = |(-1-5) +(-3-5)i| = |-6 -8i|

  = √((-6)² +(-8)²) = √100

  |z₂ -z₁| = 10 . . . . . . the diameter of a circle of radius 5

The midpoint of these two point should be the center of the circle.

  (z₁ +z₂)/2 = ((5 -1) +(5 -3)i)/2 = (4 +2i)/2 = 2 +i

  (z₁ +z₂)/2 = c . . . . . the center of the circle is the midpoint of the diameter

__₁₂₃₄

3. "Show how to determine the center of the circle."

As with any circle, the center is the <em>midpoint of any diameter</em> (demonstrated in question 2). It is also the point of intersection of the perpendicular bisectors of any chords, and it is equidistant from any points on the circle.

Any of these relations can be used to find the circle center, depending on the information you start with.

As an example. we can choose another point we know to be on the circle:

  z₄ = 6-2i

Using this point and the z₁ and z₂ above, we can write three equations in the "unknown" circle center (a +bi):

  • |z₁ - (a+bi)| = r
  • |z₂ - (a+bi)| = r
  • |z₄ - (a+bi)| = r

Using the formula for the square of the magnitude of a complex number, this becomes ...

  (5-a)² +(5-b)² = r² = 25 -10a +a² +25 -10b +b²

  (-1-a)² +(-3-b)² = r² = 1 +2a +a² +9 +6b +b²

  (6-a)² +(-2-b)² = r² = 36 -12a +a² +4 +4b +b²

Subtracting the first two equations from the third gives two linear equations in a and b:

  11 -2a -21 +14b = 0

  35 -14a -5 -2b = 0

Rearranging these to standard form, we get

  a -7b = -5

  7a +b = 15

Solving these by your favorite method gives ...

  a +bi = 2 +i = c . . . . the center of the circle

__

4. "Choose two points, one on the circle and the other not on the circle. Show, mathematically, how to determine whether or not the point is on the circle."

The points we choose are ...

  • z₃ = 3 -2i
  • z₄ = 6 -2i

We can show whether or not these are on the circle by seeing if they satisfy the equation of the circle.

  |z -c| = 5

For z₃: |(3 -2i) -(2 +i)| = √((3-2)² +(-2-i)²) = √(1+9) = √10 ≠ 5 . . . NOT on circle

For z₄: |(6 -2i) -(2 +i)| = √((6 -2)² +(2 -i)²) = √(16 +9) = √25 = 5 . . . IS on circle

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Answer:

Step-by-step explanation:

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first term a=1

an=a+(n-1)d

2n-1=1+(l-1)2

2n-1=1+2l-2

2n-1=2l-1

l=n

(i used l for number of terms)

number of terms=n

S_{n}=\frac{n}{2} (first ~term+last~term)\\=\frac{n}{2} (1+2n-1)\\=n^2

7 0
2 years ago
The population of Preston is 89,000 and is decreasing by 1.8% each year. Write a formula that models the population as a functio
Fiesta28 [93]

Answer:

P=89,000e^{-.018t}

Step-by-step explanation:

I used this equation formula and just input the numbers given:

P=P_{o}e^{rt}

Where

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P_{o} = original population

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Step-by-step explanation:

make it into a fraction

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move the decimal to the right 2 times

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