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Anni [7]
2 years ago
6

1,547.1892 rounded to the nearest hundredth

Mathematics
1 answer:
iren [92.7K]2 years ago
7 0

Answer:

I, 550

Step-by-step explanation:

Is the nearest hundredth

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What is the exact value of tan (-pie/3)?
dimaraw [331]

Answer:

The exact value of tan(π3) tan ( π 3 ) is √3 .

Step-by-step explanation:

3 0
3 years ago
Helppp pleasee!! If you can answer ASAP I would really appreciate it thank youuu.
Lady bird [3.3K]

Answer:

1. 4/7 = 16/28

Check:

(4/7)(4/4) = 16/28 = 16/28

2. 40/15 = 8/3

Check:

(40/15)/(5/5) = 8/3

3. 15/6 = 5/2

Check:

(15/6)/(3/3) = 5/2

4. 8/11 = 56/77

Check:

(8/11)(7/7) = 56/77

5. 9/2 = 63/14

Check:

(9/2)(7/7) = 63/14

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7 0
3 years ago
Can u express 9 and 9 as a mixed number ? Why or why not ? 9and 9 means fraction
Lostsunrise [7]
Yes:

1 & 0/9
   or
1 & 1/1
6 0
4 years ago
assume that random guesses are made for 9 multiple choice questions on an SAT test, so that there are n=9 trials, each with prob
Orlov [11]

Answer:

though this looks difficult. It's easier than you think. Just not visible until its visible. If I knew the answer, i would have told you... sorry.

8 0
4 years ago
Can someone help me work out this please A and B
Lesechka [4]

Answer:

see explanation

Step-by-step explanation:

(a) (i)

x² - 9 ← is a difference of squares and factors as

(x - 3)(x + 3)

(ii)

given x² + x - 12

Consider the factors of the constant term (- 12) which sum to give the coefficient of the x- term (+ 1)

The factors are + 4 and - 3, since

4 × - 3 = - 12 and 4 - 3 = + 1, hence

x² + x - 12 = (x + 4)(x - 3)

(iii)

Express the numerator/ denominator in factored form

\frac{x^2-9}{x^2+x-12}

= \frac{(x-3)(x+3)}{(x+4)(x-3)}

Cancel the (x - 3) factor on the numerator/denominator, leaving

= \frac{x+3}{x+4} with restriction x ≠ - 4

(b)

Expand the second pair of factors using FOIL

= (x + 2)(x² + 5x - 3x - 15)

= (x + 2)(x² + 2x - 15)

Multiply each term in the second factor by each term in the first factor

x(x² + 2x - 15) + 2(x² + 2x - 15) ← distribute both parenthesis

= x³ + 2x² - 15x + 2x² + 4x - 30 ← collect like terms

= x³ + 4x² - 11x - 30

Compare like terms with x³ + ax² - 11x + b

ax² with 4x² ⇒ a = 4

b with - 30 ⇒ b = - 30

3 0
3 years ago
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