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Fofino [41]
2 years ago
15

Evaluate x(–y + z) for x = –1, y = 2, and z = 5. 7 –7 3 –3

Mathematics
1 answer:
erma4kov [3.2K]2 years ago
8 0
X(-y+z)

When x is -1, y is 2, and z is 5, replace these letters with the numbers associated with them, you get

=-1(-2+5)
=-1(-2)+(-1)(5)
=2-5
=-3
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Answer with explanation:

 \rightarrow \frac{\frac{2y^2-6 y-20}{4 y+12}}{\frac{y^2+5 y+6}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{y^2-3y-10}{2 y+6}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{(y-5)(y+2)}{2 (y+3)}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{(y-5)(y+2)}{2 (y+3)}} \times {\frac{3 y^2+28 y+27}{(y+2)(y+3)}}\\\\ \rightarrow\frac{(y-5)\times(3 y^2+28 y+27)}{2 (y+3)^2}}

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=y²+3 y+2 y+6

=y×(y+3)+2×(y+3)

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=y² -5 y+2 y -10

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