Answer:
See explaination
Explanation:
Usable sequence numbers = 2^31
Transmission speed = 2^30 bps
(a)Wrap around time = (2^31 * 8 * 1)/(2^30) = 16 seconds
(b)segment size = 16 Bytes
Wrap around time = (2^31 * 8 * 16)/(2^30) = 256 seconds
(c)if we use large segment size ,which increases size of MTU in data link layer .Maximum transmission unit is the maximum size of a packet or frame that can flow across the network, without being fragmented,which lead to overhead of fragmentation at network layer.
(d)Maximum network throughput equals the TCP window size divided by the round-trip time of communications data packets.
Round trip time = 2^9 ms
window size = 2^16
Throughput = (2^16)/(2^9) = 2^7 KBps = 128 KBps = 1Mbps
Answer:
The development of diffusion dialysis for alkali separation
Explanation:
Diffusion Dialysis (DD) gives another option, perfect and planned strategy for corrosive and antacid recuperation. The most out standing preferences of DD are the perfect nature, low utilization of vitality, low establishment and working expense. Moreover, the integrations of DD (especially for corrosive recuperation frameworks) with other techniques can build the handling ability and effectiveness, so that the acids (even with low fixation) and the metal salts can be effectively recouped.
Different parameters will impact the proficiency of DD, such as film properties (particularly water content (WR) and fixed
gathering (CR)), assortment and grouping of waste arrangement, and the activity conditions (activity temperature, the stream rate, stream proportion). As needs be, critical contrasts have been accounted for for various DD frameworks: the "salt impact" is clear in the
HCl + chlorides DD frameworks, while in the H2SO4 + sulfates DD systems, the "salt impact" almost can't be watched; low retention
furthermore, high diffusivity in film are constantly seen in the solid corrosive arrangements, while in the powerless corrosive arrangement, the patterns are simply inverse; the "water assimilation" is moderately increasingly evident in the soluble base feed arrangement than that in the solid corrosive feed, and consequently the effectiveness of soluble base recuperation is lower.
The possible solution for this kind of problem is to equate the said equation base on what is ask in the problem. The design equation is use to get the Voltage out of a said circuit, thus, without any value of resistance, the left and side value of the equation should be the same, and the said problem is generally incomplete. With that, the possible answer would be -53.
Answer:
computer works on electricity
Explanation:
I guess the correct answer is class C network.
In IPv4 addressing, an IP address whose first octet is in the range of 192–223 belongs to a class C network.
