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3 years ago

7

greg spent 3 hours practicing his guitar . he spent the same amount of time practicing each of 4 songs. how many minutes did gre

g spend practicing each song?

1 answer:

umka21 [38]3 years ago

6 0

He spent 45 minutes on each song

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Write in standard form (×+4)(×-5)=4 find the value of a,b,c

Alex17521 [72]

Answer:

$x^{2}$ - x - 24 = 0

a = 1

b = 1

c = -24

Step-by-step explanation:

(x + 4)(x - 5) = 4

x(x - 5) = $x^{2}$ - 5x

4(x - 5) = 4x - 20

$x^{2}$ - 5x + 4x - 20 = 4

$x^{2}$ - x - 20 = 4

$x^{2}$ - x - 20 - 4 = 0

$x^{2}$ - x - 24 = 0

a = 1

b = 1

c = -24

4 0

3 years ago

Twelve education students, in groups of four, are taking part in a student-teacher program. Mark cannot be in the first group be

aliya0001 [1]

The answer is 330. Or answer B

7 0

3 years ago

Read 2 more answers

3. The curve C with equation y=f(x) is such that, dy/dx = 3x^2 + 4x +k

Andreas93 [3]

a. Given that y = f(x) and f(0) = -2, by the fundamental theorem of calculus we have

$\displaystyle \frac{dy}{dx} = 3x^2 + 4x + k \implies y = f(0) + \int_0^x (3t^2+4t+k) \, dt$

Evaluate the integral to solve for y :

$\displaystyle y = -2 + \int_0^x (3t^2+4t+k) \, dt$

$\displaystyle y = -2 + (t^3+2t^2+kt)\bigg|_0^x$

$\displaystyle y = x^3+2x^2+kx - 2$

Use the other known value, f(2) = 18, to solve for k :

$18 = 2^3 + 2\times2^2+2k - 2 \implies \boxed{k = 2}$

Then the curve C has equation

$\boxed{y = x^3 + 2x^2 + 2x - 2}$

b. Any tangent to the curve C at a point (a, f(a)) has slope equal to the derivative of y at that point:

$\dfrac{dy}{dx}\bigg|_{x=a} = 3a^2 + 4a + 2$

The slope of the given tangent line $y=x-2$ is 1. Solve for a :

$3a^2 + 4a + 2 = 1 \implies 3a^2 + 4a + 1 = (3a+1)(a+1)=0 \implies a = -\dfrac13 \text{ or }a = -1$

so we know there exists a tangent to C with slope 1. When x = -1/3, we have y = f(-1/3) = -67/27; when x = -1, we have y = f(-1) = -3. This means the tangent line must meet C at either (-1/3, -67/27) or (-1, -3).

Decide which of these points is correct:

$x - 2 = x^3 + 2x^2 + 2x - 2 \implies x^3 + 2x^2 + x = x(x+1)^2=0 \implies x=0 \text{ or } x = -1$

So, the point of contact between the tangent line and C is (-1, -3).

7 0

2 years ago

Can someone tell me if this is right?

morpeh [17]

Answer:

yes it is right no one is mistake

5 0

3 years ago

Read 2 more answers

Need help its due at 7 pm so take your time

s344n2d4d5 [400]

Answer:

141x

Step-by-step explanation:

I just did PEMDAS

3x^2-33x-180

multiplied 3x^2 and got 6x

Subbed 180 by 33 and got 147x

then I subbed 147x by 66x and got 141x

3 0

3 years ago