<span>Part A: M = 12x. (x hours at the rate of $12/per hour)
Part B: T = 12 * 30 + 15y. ( 30 hours per week at the rate of $12 per
hour plus y hours at the rate of $15 per hour)
Part C: Let us first find out the amount earned through regular working hours and overtime hours.
Regular hours in a week is 30 at the rate of $12 per hour. It comes to 12*30 = $360
The remaining amount, 510-360 = 150, is earned through overtime. Overtime rate is $15 per hour. So the number of hours worked overtime = 150/15 = 10
Total hours worked during the week = 30 + 10 = 40.</span>
Complementary angles are 90 degrees,so if the angle is 64 degrees more,you just only have to add 90+64=154.
The measure of the angle is 154 degrees
Hope i helped.
Remember:complimentary angles add up to 90 while supplementary angles add up to 180.
:<span> </span><span>You need to know the derivative of the sqrt function. Remember that sqrt(x) = x^(1/2), and that (d x^a)/(dx) = a x^(a-1). So (d sqrt(x))/(dx) = (d x^(1/2))/(dx) = (1/2) x^((1/2)-1) = (1/2) x^(-1/2) = 1/(2 x^(1/2)) = 1/(2 sqrt(x)).
There is a subtle shift in meaning in the use of t. If you say "after t seconds", t is a dimensionless quantity, such as 169. Also in the formula V = 4 sqrt(t) cm3, t is apparently dimensionless. But if you say "t = 169 seconds", t has dimension time, measured in the unit of seconds, and also expressing speed of change of V as (dV)/(dt) presupposes that t has dimension time. But you can't mix formulas in which t is dimensionless with formulas in which t is dimensioned.
Below I treat t as being dimensionless. So where t is supposed to stand for time I write "t seconds" instead of just "t".
Then (dV)/(d(t seconds)) = (d 4 sqrt(t))/(dt) cm3/s = 4 (d sqrt(t))/(dt) cm3/s = 4 / (2 sqrt(t)) cm3/s = 2 / (sqrt(t)) cm3/s.
Plugging in t = 169 gives 2/13 cm3/s.</span>
Answer:
8
Step-by-step explanation:
Step-by-step explanation:
