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geniusboy [140]
3 years ago
6

Which of the following is the scatter plot of the data below?

Mathematics
2 answers:
monitta3 years ago
5 0
C, because on the rest of the graphs 4,10 is not located on the graphs but on c, it is, which makes c the answer.
soldier1979 [14.2K]3 years ago
4 0
If you look at the points, you can find out
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YES PLS HELP WITH MY GEOMETRY
noname [10]

Answer:

(-7, 31)

Step-by-step explanation:

To solve this equation, simply plug in the numbers. For example, with -3 and -11, you simply plug them into the equation:

  • -11 = -5 (-3) - 4
  • After you solve this, you'll see the equation does not come out to -11; rather, it comes out to +11.

Repeat this with all equations, and you will see which are correct. Be careful, however, and remember which number goes into which value.

6 0
4 years ago
Find the product 54×653
musickatia [10]
35262 Is the answer just multiply 54 x65 and get the answer then multiply the answer by 3
7 0
3 years ago
How many feet are in 5 meters?
horrorfan [7]
This should hel.p. you out

8 0
3 years ago
Read 2 more answers
Use Random number generator and simulate 1000 long columns, for each of the three cases. Example: for the Car type 1, use Number
sertanlavr [38]

Answer:

Step-by-step explanation:

The question is incomplete since they do not give information about the Car type 3.

We will do it in a generic way, we will say that the Car type 3 has a mean of M and a standard deviation SD.

We would be:

P (CT3 <550) = P [z <(550 - X) / SD]

Now if we give it values, for example that X = 600 and SD = 120

It would remain:

P (CT3 <550) = P [z <(550 - 600) / 120]

P (CT3 <550) = P [z <-0.42]

We look for this value in the normal distribution table (attached) and it shows us that the probability is approximately 0.3372, that is, 33.72%

What you need to do is replace the X and SD values of theCar type 3 in the equation above how I just did and you will get the result.

7 0
3 years ago
Hi Plz help me with this question
inessss [21]
Answer: 4,-6
Not 100% sure
3 0
3 years ago
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