Find the number of permutations in the word fission 1020 1500 1260 2400
1 answer:
There are 7 letters in fission, which we'll use as a factorial in the numerator. Of those 7 letters, there are two I's and two S's. To account for these repeating letters, we'll use the factorials of how many times the letters repeat and plug them into the denominator.
The factorial of 7 should be your numerator, and two factorials of 2 should be your denominator:
There are 1260 different permutations of the word fission.
The factorial of 7 should be your numerator, and two factorials of 2 should be your denominator:
There are 1260 different permutations of the word fission.
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95% of scores fall within +/-2 standard deviations from the mean
Answer:
a) The proportion of states would you expect to have more than 65% of their traffic fatalities from drunk driving is 0.59518.
b) The 25th percentile of this distribution is a 0.5231 proportion of deaths due to drunk driving.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the percentile of this measure.
In this problem, we have that:
Mean 0.569 and standard deviation 0.068. So
a. What proportion of states would you expect to have more than 65% of their traffic fatali- ties from drunk driving?
This is the value of X when Z has a pvalue of 0.65.
Z has a pvalue of 0.65 between and
. So, we use
The proportion of states would you expect to have more than 65% of their traffic fatalities from drunk driving is 0.59518.
b. What proportion of deaths due to drunk driving would you expect to be at the 25th percentile of this distribution?
This is the value of X when Z has a pvalue of 0.25.
Z has a pvalue of 0.65 between and
. So, we use
The 25th percentile of this distribution is a 0.5231 proportion of deaths due to drunk driving.