If p = 2, insert the value of p.
2^3 = 2 x 2 x 2 = 4 x 2 = 8
so p^3 = 8
1y - 1/x = 1/60 = x*y =60 = x=60/y
3y - 2(60/y) = 6
3y^2-120=6y
3(y^2-40-2y) =0
y^2-40-2y=0
y = 7.4
3(7.4)-2x=6
22.2-2x = 6
2x = -16.2
x = -8.1
Answer:
Each time, t, is associated with exactly one car value, y.
Step-by-step explanation:
Answer:
2.7
Step-by-step explanation:
0.5+1.2+1= 2.7