The fundamental theorem of algebra states that a polynomial with degree n has at most n solutions. The "at most" depends on the fact that the solutions might not all be real number.
In fact, if you use complex number, then a polynomial with degree n has exactly n roots.
So, in particular, a third-degree polynomial can have at most 3 roots.
In fact, in general, if the polynomial
has solutions
, then you can factor it as

So, a third-degree polynomial can't have 4 (or more) solutions, because otherwise you could write it as

But this is a fourth-degree polynomial.
Answer:
there must be at least 6 chaperones
Step-by-step explanation:
25 x 3= 75 so 2 chaperons x 3= 6 with a remainder of 5 students
Answer:
Step-by-step explanation:
b^2 - 4ac > 0
(-8)^2 - 4(1)(-2) = 64 + 8 = 72
two solutions
8 * 5 = 40
40 * 4 = 160
160 * 12 = 1,920
Answer: $1,920