It is pi x 11(x2 to get diameter) so it would be 69.08...
For this case we have the following equation:
![\sqrt [4] {2x-8} + \sqrt [4] {2x + 8} = 0](https://tex.z-dn.net/?f=%5Csqrt%20%5B4%5D%20%7B2x-8%7D%20%2B%20%5Csqrt%20%5B4%5D%20%7B2x%20%2B%208%7D%20%3D%200)
If we subtract both sides of the equation
we have:
![\sqrt [4] {2x-8} = - \sqrt [4] {2x + 8}](https://tex.z-dn.net/?f=%5Csqrt%20%5B4%5D%20%7B2x-8%7D%20%3D%20-%20%5Csqrt%20%5B4%5D%20%7B2x%20%2B%208%7D)
To eliminate the radical we raise both sides of the equation to the fourth power:
![(\sqrt [4] {2x-8}) ^ 4 = (- \sqrt [4] {2x + 8}) ^ 4](https://tex.z-dn.net/?f=%28%5Csqrt%20%5B4%5D%20%7B2x-8%7D%29%20%5E%204%20%3D%20%28-%20%5Csqrt%20%5B4%5D%20%7B2x%20%2B%208%7D%29%20%5E%204)
Answer:
Option D
Answer:
195
Step-by-step explanation:
If there are x boys, then there are x+26 girls. Hence, we write the equation,
x+(x+26)=364
Solve for x:
2x+26=364
2x-338
x=169
So there are 169+26 =195 girls
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Let me see if I can decipher that :P
3/(3x)+1/x+4=10/(7x) first we need to make all terms have a common denominator of 21x...
(21+21+84x)/(21x)=30/(21x) multiplying both sides by 21x leaves you with
21+21+84x=30 combine like terms on left side
42+84x=30 subtract 42 from both sides
84x=-12 divide both sides by 84
x=-1/7