Answer:

Step-by-step explanation:
Given
--- proportion that have very little confidence
--- sample
Required
Determine the probability that exactly 5 have very little confidence
This question will be solved using binomial probability:

In this case: x = 5.
So, we have:




Answer:
10 squared units
Step-by-step explanation:
This triangle is pretty easy since it creates a right triangle. So the base length and height length are pretty easy to identify.
The area of a triangle is .5*base*height.
The base length after drawing the points is a horizontal so just count it or do 4-0=4.
The height length after drawing the points is a vertical so just count it or do 4-(-1)=4+1=5.
So the area of the triangle is .5*4*5=.5(20)=10 units squared.
Now if you didn't fill like drawing it and you knew how to find the determinant.
You just compute
.5 times det| 0 -1 1 |
| 0 4 1 |
| 4 -1 1 |
.5[ 0 det| 4 1 | - -1 det| 0 1 | + 1 det | 0 4 | ]
| -1 1 | | 4 1 | | 4 -1 |
.5[ 0 - -1(0-4) + 1(0-16)]
.5[ 0 -4 -16]
.5[-20]
-10
And if you get a negative just take the absolute value of it giving you 10.
Answer: (1,-2) (0,-4) (-4,0)
Step-by-step explanation:
<span>If M is the midpoint of CD, CM = 2x+3 and MD = 3x-6, then:
MD = CM
3x - 6 = </span>2x + 3
3x - 2x = 3 + 6
x = 9
CM = 2x+3 = 2*9+3 18+3 = 21
MD = CM = 21
CD = CM + MD = 21 + 21 = 42