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ZanzabumX [31]
4 years ago
5

Semicircle arc AB,AC,BD and CD divide the circle above in to regions. The points shown along the diameter AD divided in to 6 equ

al parts. If AD=6 what is the total area of the shaded region?

Mathematics
1 answer:
frozen [14]4 years ago
6 0
Area semicircle = π * r^{2} / 2;

 the total area of the shaded region = 2 * [ π* ( BD / 2)^{2} / 2 - π* ( CD / 2)^{2} / 2 ] = 4π - 1π = 3π.
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Zero

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4 0
3 years ago
Suppose ∠A and ∠B are complements, while ∠B and ∠C are supplements. If m∠A=3x+17, m∠B=55−x, and m∠C=67(x/3−1), then m∠A=44, m∠B=
d1i1m1o1n [39]

The statement is true if A and ∠B are complements, while ∠B and ∠C are supplements.

<h3>What is an angle?</h3>

When two lines or rays converge at the same point, the measurement between them is called a "Angle."

We have:

∠A and ∠B are complements, while ∠B and ∠C are supplements.

∠A + ∠B = 90 degree

3x + 17 + 55 - x = 90

2x = 18

x = 9

Angle ∠B and angle ∠C are supplementary:

∠B + ∠C = 180

55 -x + 67(x/3  - 1) = 180

x = 9

Put the value of x and find angles A, B, and C.

m∠A = 44

m∠B = 46

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∠A + ∠B = 90

∠B + ∠C = 180

The above statement is true.

Thus, the statement is true if A and ∠B are complements, while ∠B and ∠C are supplements.

Learn more about the angle here:

brainly.com/question/7116550

#SPJ

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