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nirvana33 [79]
3 years ago
9

An experiment consists of rolling a die, flipping a coin, and spinning a spinner divided into 4 equal regions. The number of ele

ments in the sample space of this experiment is
12

3

6

48
Mathematics
2 answers:
Delvig [45]3 years ago
5 0

Answer:

48

Step-by-step explanation:

There are 3 events that are taking place.

Rolling a die which has 6 possible outcomes.

Flipping a coin which has 2 possible outcomes.

Spinning a spinner which has 4 possible outcomes.

Since the outcome of each event is independent of the other, the total possible outcomes will be equal to the product of outcomes of each event.

i.e.

Total outcomes = 6 x 2 x 4 = 48

The sample space of the experiment contains all the possible outcomes. so the number of elements in the sample space of this experiment will be 48

pav-90 [236]3 years ago
5 0

<u>Answer:</u>

The correct answer option is 48.

<u>Step-by-step explanation:</u>

Here in this experiment, three events are taking place that include rolling a die, flipping a coin and spinning a spinner.

The possible outcomes of each of these events are:

Rolling a die - 6

Flipping a coin - 2

Spinning a spinner - 4

Therefore, we can find the number of elements in the sample space of this environment by multiplying their possible outcomes.

Number of elements = 6 × 2 × 4 = 48

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