Question

1. The head of a rattlesnake can accelerate 50.0 m/s in striking a victim. If a car could do

Answer 1

Answer: 0.492 s

Explanation:

We can use the following equation to solve this problem:

$V=V_{o}+a.t$

Where:

$V=24.6 m/s$ is the car’s final velocity

$V_{o}=0 m/s$ is the car’s initial velocity  (it starts from rest)

$a=50 m/s^{2}$ is the car's acceleration  

$t$ is the time we have to find

Isolating $t$:

$t=\frac{V-V_{o}}{a}$

$t=\frac{24.6 m/s-0 m/s}{50 m/s^{2}}$

Finally:

$t=0.492 s$