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hichkok12 [17]
3 years ago
13

A stationary wave of two loops is formed on a string of length 1.2m. Sketch the pattern and state the wavelength. Label two poin

ts P and Q which are in phase

Physics
1 answer:
jeka943 years ago
7 0

Explanation:

Throughout this chapter, we have been studying traveling waves, or waves that transport energy from one place to another. Under certain conditions, waves can bounce back and forth through a particular region, effectively becoming stationary. These are called standing waves.

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At a given point in its orbit, the moon is 2.4 x 10^5 miles from earth. How long does it take light from a source on earth to re
Mice21 [21]

Answer:

Total time= 2.56 s

Explanation:

Given that

Distance = 2.4\times 10^5\ miles

So distance = 386242560 m

Velocity of light

C= 3\times 10^8\ m/s

We know that

Distance = velocity x time

Now by putting then values

time=\frac{386242560}{3\times 10^8}

t=1.28 s

So the total time = 2 x 1.28

total time= 2.56 s

8 0
4 years ago
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Which of the following is NOT an example of the 3rd law of motion (for every Action, there is an equal but opposite reaction?
Vlad1618 [11]

Answer:

C a basketball player pushes into another one and they both fall to the left

Explanation:

I believe his is the answer because I don't see any force and not enough reaction

6 0
2 years ago
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Where are protons, neutrons, and electrons in the atom?
PilotLPTM [1.2K]

Answer:

The protons and the neutron are located in the nucleus and the electrons is the outermost region

8 0
3 years ago
What is the independent variable on this graph??
Veronika [31]
Temperature. X-axis is always the independent variable.
3 0
4 years ago
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A stone is thrown vertically upward with an initial speed of 24.7 m/s. Neglect air resistance. The speed of the stone when it is
fredd [130]

Answer:

The speed of the stone when it is 4.66 m higher is 236.057 m/s.

Explanation:

Given the initial velocity and vertical distance, we can use the fourth kinematic equation (v^{2} =v_{o}^{2}+2ay) to find v final, or the v to the left of the equal sign. We know v_{o} (initial velocity) is 24.7 m/s, y (change in vertical distance) is 4.66 m, and a is another way to write g (acceleration due to gravity), or 9.8 m/s^{2}.

From here you could plug in the values and solve for v final, but to make the solving process simpler, we can simplify the given equation, <em>then </em>plug in the known values.

To isolate v final, we can take the square root of v^{2} and do the same to the right side of the equation. Therefore, we can find v final with: v_{o} \sqrt{2ay}, where v initial is outside of the square root because it squared...

If we plug in the known values to the simplified equation, we get: v=24.7m/s*\sqrt{2(9.8m/s)(4.66 m)}

The final answer is 236.057 m/s.

4 0
2 years ago
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