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muminat
4 years ago
15

If one would dissolve 60g of sugar in 300g of water, what would the concentration of sugar in this syrup be?

Mathematics
1 answer:
Pie4 years ago
3 0
Density of water = 1000 kg/m^3
1 m^3 = 1000 litres

Therefore,
1000 kg/1000 l => 1 kg/l => 1000 g/l

Then, 300 g of water = 300/1000 l = 0.3 l

The concentration of the syrup =  mass/amount of water = 60 g/0.3 l = 200 g/l 
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Answer:

Bill should use 4.5 pounds of the candy costing 45 cents and 2.5 pounds of the candy costing 65 cents.

Step-by-step explanation:

With the information provided, you can say that the sum of the pounds of each type of candy is equal to 7, which can be expressed as:

x+y=7

Also, the statement indicates the 7 pound box costs $3.65 and you can say that the sum of the results of multiplying the price of each candy for the number of pounds is equal to $3.65, which is:

0.45x+0.65y=3.65

You have the following equations:

x+y=7 (1)

0.45x+0.65y=3.65 (2)

Now, you have to solve for x in (1):

x=7-y (3)

Then, you have to replace (3) in (2):

0.45(7-y)+0.65y=3.65

3.15-0.45y+0.65y=3.65

0.20y=0.50

y=0.50/0.20

y=2.5

Finally, you can replace the value of y in (3) to find x:

x=7-y

x=7-2.5

x=4.5

According to this, the answer is that Bill should use 4.5 pounds of the candy costing 45 cents and 2.5 pounds of the candy costing 65 cents.

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Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

(x / -5) + 7 ≥ 1

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