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Ivahew [28]
3 years ago
11

Suppose a fair six sided die has been relabeled so that the 6 is replaced with another 5,i.e., the sides read 1,2,3,4,5,5. If th

e die is rolled five times, what is the probability that we roll five distinct values
Mathematics
1 answer:
Anvisha [2.4K]3 years ago
8 0

Answer:

P(rolling five distinct values) = 1/3888

Step-by-step explanation:

We are told that I the fair sided dice, 6 is replaced with 5.

Thus,the numbers are now;

1,2,3,4,5,5.

This means a total of 6 possible numbers appearing.

Now, in these 6 numbers there are only 5 distinct numbers since 5 occurs twice.

P(1) = 1/6

P(2) = 1/6

P(3) = 1/6

P(4) = 1/6

P(5) = 2/6

Thus,probability of rolling 5 distinct values = 1/6 × 1/6 × 1/6 × 1/6 × 2/6 = 1/3888

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Simplify. (-2)-3 -8 - 8 user: simplify. 6x-2
Vinvika [58]
If you would like to simplify <span>(-2)-3 -8 - 8 and 6x - 2, you can do this using the following steps:

</span><span>(-2)-3 -8 - 8 = - 2 - 3 - 8 - 8 = - 5 - 8 - 8 = - 13 - 8 = - 21

6x - 2 = 2 * (3x - 1)

The correct result would be - 21 and </span><span>2 * (3x - 1).</span>
3 0
2 years ago
Camden is going to invest $600 and leave it in an account for 12 years. Assuming the
UkoKoshka [18]

~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$920\\ P=\textit{original amount deposited}\dotfill & \$600\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &12 \end{cases}

920=600e^{\frac{r}{100}\cdot 12}\implies \cfrac{920}{600}=e^{\frac{3r}{25}}\implies \cfrac{23}{15}=e^{\frac{3r}{25}}\implies \log_e\left( \cfrac{23}{15} \right)=\log_e\left( e^{\frac{3r}{25}} \right) \\\\\\ \ln\left( \cfrac{23}{15} \right)=\cfrac{3r}{25}\implies 25\cdot \ln\left( \cfrac{23}{15} \right)=3r\implies \cfrac{25\cdot \ln\left( \frac{23}{15} \right)}{3}=r \\\\\\ 3.5620\approx r\implies \stackrel{\%}{3.56}\approx r

7 0
2 years ago
Fifteen years later, a man will be two times as old as he was 15 years ago. How old is he now?
Inga [223]

Answer:

Let the present age of the man be x years.

Age of the man 15 years ago =(x−15) years and

Age of the man 15 years later =(x+15) years

According to the given condition, we have

(x+15)=2(x−15)

⇒x+15=2x−30

⇒x−2x=−30−15

⇒−x=−45 or x=45 years

Hence, the present age of the man is 45 years.

Step-by-step explanation:

Hope it helps you..

Your welcome in advance..

(◍•ᴗ•◍)

6 0
2 years ago
Read 2 more answers
1. Find the slope of the line that goes through the points (2, 5) and (6, 7)
ella [17]

Answer:

\displaystyle m = \frac{1}{2}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)
  • Slope Formula: \displaystyle m = \frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Point (2, 5)

Point (6, 7)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute in points [Slope Formula]:                                                              \displaystyle m = \frac{7-5}{6-2}
  2. [Fraction] Subtract:                                                                                           \displaystyle m = \frac{2}{4}
  3. [Fraction] Simplify:                                                                                            \displaystyle m = \frac{1}{2}
7 0
2 years ago
12. Find the value of x.<br> (11x - 151°<br> (5x - 13°
Step2247 [10]

Answer:

Step-by-step explanation:

I guess the angles are supplementary, which means they have a sum of 180º.

11x - 15 + 5x - 13 = 180

16x -28 = 180

16x = 208

x = 13

4 0
2 years ago
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