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Ivahew [28]
3 years ago
11

Suppose a fair six sided die has been relabeled so that the 6 is replaced with another 5,i.e., the sides read 1,2,3,4,5,5. If th

e die is rolled five times, what is the probability that we roll five distinct values
Mathematics
1 answer:
Anvisha [2.4K]3 years ago
8 0

Answer:

P(rolling five distinct values) = 1/3888

Step-by-step explanation:

We are told that I the fair sided dice, 6 is replaced with 5.

Thus,the numbers are now;

1,2,3,4,5,5.

This means a total of 6 possible numbers appearing.

Now, in these 6 numbers there are only 5 distinct numbers since 5 occurs twice.

P(1) = 1/6

P(2) = 1/6

P(3) = 1/6

P(4) = 1/6

P(5) = 2/6

Thus,probability of rolling 5 distinct values = 1/6 × 1/6 × 1/6 × 1/6 × 2/6 = 1/3888

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What is the value of -6x3-y2-3xy if x=-2 and y=4
Svetach [21]
<h2>Hello!</h2>

The answer is:

The value of the given expression evaluated with x equals to -2 and y equals to 4, is equal to 56 units.

<h2>Why?</h2>

To solve the problem, we need to evaluate both variables for the given values:

x=-2

and

y=4

So, we are given the expression:

-6x^{3}-y^{2}-3xy

Then, evaluating the given values for both variables, we have:

-6*(-2)^{3}-(4)^{2}-3*(-2)*(4)=(-6*-8)-(16)+24=48-16+24=56

Hence, we have that the answer is:

The value of the given expression evaluated with x equals to -2 and y equals to 4, is equal to 56 units.

Have a nice day!

5 0
3 years ago
Read 2 more answers
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