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Ivahew [28]
3 years ago
11

Suppose a fair six sided die has been relabeled so that the 6 is replaced with another 5,i.e., the sides read 1,2,3,4,5,5. If th

e die is rolled five times, what is the probability that we roll five distinct values
Mathematics
1 answer:
Anvisha [2.4K]3 years ago
8 0

Answer:

P(rolling five distinct values) = 1/3888

Step-by-step explanation:

We are told that I the fair sided dice, 6 is replaced with 5.

Thus,the numbers are now;

1,2,3,4,5,5.

This means a total of 6 possible numbers appearing.

Now, in these 6 numbers there are only 5 distinct numbers since 5 occurs twice.

P(1) = 1/6

P(2) = 1/6

P(3) = 1/6

P(4) = 1/6

P(5) = 2/6

Thus,probability of rolling 5 distinct values = 1/6 × 1/6 × 1/6 × 1/6 × 2/6 = 1/3888

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Answer:5625 yards

Step-by-step explanation:

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6/15+5/15=11/15

(15/15)-(11/15)=4/15

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3 years ago
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ss7ja [257]
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</span><span>Explanation:
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We can write it as:

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If power of x in numerator is equal to the power of x in denomenator, then the horizontal asymptote will be y=(co-efficient in numerator)/(co-efficient in denomenator).
If power of x in numerator is greater than the power of x in denomenator, then there will be no horizontal asymptote.

In above case, 0 < 1, therefore, the horizontal asymptote is y = 0
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3 years ago
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