Answer:
50%
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given:
u = 1, 0, -4
In unit vector notation,
u = i + 0j - 4k
Now, to get all unit vectors that are orthogonal to vector u, remember that two vectors are orthogonal if their dot product is zero.
If v = v₁ i + v₂ j + v₃ k is one of those vectors that are orthogonal to u, then
u. v = 0 [<em>substitute for the values of u and v</em>]
=> (i + 0j - 4k) . (v₁ i + v₂ j + v₃ k) = 0 [<em>simplify</em>]
=> v₁ + 0 - 4v₃ = 0
=> v₁ = 4v₃
Plug in the value of v₁ = 4v₃ into vector v as follows
v = 4v₃ i + v₂ j + v₃ k -------------(i)
Equation (i) is the generalized form of all vectors that will be orthogonal to vector u
Now,
Get the generalized unit vector by dividing the equation (i) by the magnitude of the generalized vector form. i.e

Where;
|v| = 
|v| = 
= 
This is the general form of all unit vectors that are orthogonal to vector u
where v₂ and v₃ are non-zero arbitrary real numbers.
Answer:
a² + 4 a + 4
Step-by-step explanation:
( a + 2 ) ( a + 2 )
Expand brackets
a² + 2 a + 2 a + 4
Simplify
a² + 4 a + 4
Answer:
Fifty percent of the data values lies between 34 and 46.
It is unlikely that there are any outliers.
Step-by-step explanation:
drawing out this box plot and looking online for a picture of the same plot:
From the box plot:
median=46
Q1=42
Q3=70
Q3-Q1= IQR=70-42=28
max=76
min=34
Range=max-min=76-34=42
no outliers seen from boxplot