Distance=speed*time
distance traveled by plane A after 40 minutes:
distance=570×40/60=380 miles
Distance traveled by B after 40 minutes
distance=20/60×585=195 miles
Thus the distance between them will be given using cosine law:
c^2=a^2+b^2-2ab Cos C
thus we shall have:
c^2=380^2+195^2-2*380*195*cos22
c^2=45016.35275
c=212.171 miles
Thus the distance between them after 40 minutes is 212.171 miles
The complete question in the attached figure
Part A) How much sand is currently in the container?
[sand currently in the container]=(5)*(4 1/2)*(2.25)-----> (5)*(4.5)*(2.25)
[sand currently in the container]=50.625 in³
the answer Part a) is 50.625 in³Part B) How much more sand could the container hold before?
[sand could the container hold before]=[5*4.5*3]-[50.625]
[sand could the container hold before]=[67.5]-[50.625]------> 16.875 in³
the answer Part B) is 16.875 in³
Part C) What percent of the container is filled with sand?
the volume of container is [5*4.5*3]=67.5 in³
the volume filled with sand=50.625 in³
therefore
if 100%----------------> 67.5 in³
X---------------------> 50.625 in³
X=(50.625*100)/67.5=75 %
the answer Part C) is 75%
6x3=18
20-18=2
Therefore the answer is 6 times
Answer:
12 feet.
Step-by-step explanation:
h= -(2)^2+8(2)
h= -4+16
h= 12