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Nataly [62]
3 years ago
6

You please help with multiplication and division equations

Mathematics
1 answer:
8090 [49]3 years ago
8 0
You already posted this one lol I answered it already.
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Help me solve for the right triangle
AleksAgata [21]

Answers:

B = 50

a = 10.9

c = 17.0

================================================

Explanation:

This is a right triangle, so the acute angles are complementary, meaning they add to 90

B+40 = 90

B+40-40 = 90-40

B = 50

Also, because this is a right triangle, we can use trig ratios to compute the missing sides

tan(angle) = opposite/adjacent

tan(40) = a/13

a = 13*tan(40)

a = 10.908

a = 10.9

cos(angle) = adjacent/hypotenuse

cos(40) = 13/c

c*cos(40) = 13

c = 13/cos(40)

c = 17.0

note: make sure your calculator is in degree mode

7 0
3 years ago
Solve 2(x+1)=2x+2<br><br> A. All real numbers<br> B. No solution<br> C. 0<br> D. 1
frez [133]

Answer: All real numbers

Step-by-step explanation:

All real numbers

Interval Notation:

( − ∞ , ∞ )

(-∞,∞)

5 0
3 years ago
Read 2 more answers
Please help. I will give brainliest!
Andrej [43]

Answer:

Step-by-step explanation:

How to Find Outliers Using the Interquartile Range(IQR)

Step 1: Find the IQR, Q1(25th percentile) and Q3(75th percentile). ...

Step 2: Multiply the IQR you found in Step 1 by 1.5: ...

Step 3: Add the amount you found in Step 2 to Q3 from Step 1: ...

Step 3: Subtract the amount you found in Step 2 from Q1 from Step 1:

7 0
3 years ago
Drag each shape to the correct location on the image. Not all shapes will be used. Complete each shape with the missing half so
Sav [38]

Answer:

  see attached

Step-by-step explanation:

Perhaps the easiest way to do this is to draw the needed shape in the box, then locate it among the answer choices. Use the identifying features such as dot location and direction of arrow (or tail).

__

Left-to-right, this is what you're trying to match:

  1. tail on the right, dot in the tail
  2. tail on the left, dot in the fin
  3. tail on the right, dot in the nose
  4. tail on the left, dot in the center

8 0
2 years ago
Read 2 more answers
Jessie draws triangle ABC on a coordinate grid. The slope of line segment AB is Jessie then transforms triangle
balu736 [363]

Answer:

1) Supports Jessie's Claim

2) Does Not Support Jessi's Claim

3) Supports Jessie's Claim

4) Does Not Support Jessi's Claim

Step-by-step explanation:

The given transformations are;

1) Rotation of 180° around the origin

For a rotation of 180° around the origin, either clockwise or anti clockwise, for a given coordinate of the preimage (x, y), the coordinate of the image is (-x, -y)

Therefore, whereby the slope of the preimage, given two points (0, 0) and (2, 2), = (2 - 0)/(2 - 0) = 1

For the image with the points (0, 0) and (-2, -2), we have;

(-2 - 0)/(-2 - 0) = 1

Therefore, the slope of the preimage and the image are equal

Therefore, supports Jessie's Claim

2) For a reflection across the line y = 2, we have

We note that the line y = 2 is parallel to the x-axis

For a reflection across the x-axis, for a preimage (x, y), we have the coordinates of the image (x, -y)

However for the reflection across the line y = 2, we have;

For a preimage, (x, y), the coordinate of the image is (x, -y+4)

Given two points, of the preimage (0, 0) and (2, 2), we have the image given as (0, 4) and (2, -2 + 4) = (2, 2);

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (2 - 4)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

3) For a translation up 1.25 units, we note that the difference in the y and x values of the coordinates of the preimage and the image will be equal when finding the slope, and therefore, the slope of the figure of the preimage and the slope of the figure of the image will be equal

Therefore, supports Jessie's Claim

4) For a reflection across the x-axis, a point on the preimage, with coordinates (x, y) will form a point on the image with coordinates (x, - y)

For a preimage with points (0, 0) and (2, 2), we have the image as (0, 0) and (2, -2)

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (-2 - 0)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

6 0
3 years ago
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