Answer:
a) 95% of the widget weights lie between 29 and 57 ounces.
b) What percentage of the widget weights lie between 12 and 57 ounces? about 97.5%
c) What percentage of the widget weights lie above 30? about 97.5%
Step-by-step explanation:
The empirical rule for a mean of 43 and a standard deviation of 7 is shown below.
a) 29 represents two standard deviations below the mean, and 57 represents two standard deviations above the mean, so, 95% of the widget weights lie between 29 and 57 ounces.
b) 22 represents three standard deviations below the mean, and the percentage of the widget weights below 22 is only 0.15%. We can say that the percentage of widget weights below 12 is about 0. Equivalently we can say that the percentage of widget weights between 12 an 43 is about 50% and the percentage of widget weights between 43 and 57 is 47.5%. Therefore, the percentage of the widget weights that lie between 12 and 57 ounces is about 97.5%
c) The percentage of widget weights that lie above 29 is 47.5% + 50% = 97.5%. We can consider that the percentage of the widget weights that lie above 30 is about 97.5%
Answer:
6 cm
Step-by-step explanation:
Vcuboid = lwh
⇒ h = Vcuboid ÷ lw
∴ h = 540 cm³ ÷ 90 cm²
⇒ h = 6 cm
B )5 15 ;9 27 its proportion
Answer:
Step-by-step explanation:
The brackets are absolute value. The absolute value of a number is the distance from zero which can never be negative (distance can’t be negative). Btw the answer is 2
Answer:
use the quadruple double schlop schlop theorum
Step-by-step explanation: