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BabaBlast [244]
4 years ago
9

What would be an analogy for transcription and translation?

Biology
1 answer:
ohaa [14]4 years ago
6 0
Writing down of the French language in scentences. Then getting someone to read it for you (in your language)
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You cross a true-breeding red-flowered snapdragon with a true-breeding white-flowered snapdragon. all of the f1 are pink. what c
o-na [289]
Red and white show incomplete dominance

Incomplete dominance is a form of intermediate inheritance in which one allele for a specific trait is not completely expressed over its paired allele. This results in a third phenotype in which the expressed physical trait is a combination of the phenotypes of both alleles.

Hope this helps! I'm happy to help with any other questions you might have :)

8 0
3 years ago
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Put these processes of the water cycle in the correct order, starting from the moment the sun transfers it's energy
Volgvan

is there any choices?

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3 years ago
The consequences of particular diseases are features of _____.
USPshnik [31]
The answer would be: <span>secondary aging.</span>

There is two type of aging, primary and secondary aging. Primary aging is the one that happens because of the age so it can't be prevented. Secondary aging happens because of bad diet and disease, so it can be prevented by doing healthy lifestyle or medicine.
8 0
3 years ago
Jim was observing a frog embryo in which the brain and spinal cord were formed. In what stage is the embryo? (A) neurula stage (
Leno4ka [110]
"N<span>eurula stage" is the stage among the following choices given in the question that is the stage of the embryo Jim was watching. The correct option among all the options that are given in the question is the first option or option "A". I hope that this is the answer that has actually come to your great help.</span>
5 0
4 years ago
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from 150 gram of Urea 3 into 10 power 23 molecules are removed then how many molecules are remain....​
Vikki [24]

Answer:

Amount remaining = 1.205 * 10²⁴ molecules of urea

Explanation:

The molecular formula of urea is CH₄N₂O. It has a molar mass of 60 g/mol.

Number of moles of urea present in 150 g of urea = mass/molar mass

Number of moles = 150 g/ 60 g/mol = 2.5 moles of urea

I mole of urea contains 6.02 * 10²³ molecules of urea

2.5 moles of urea will contain 2.5 * 6.02 * 10²³ molecules of urea = 1.505 * 10²⁴ molecules of urea

If 3 * 10²³ molecules are removed from 1.505 * 10²⁴ molecules of urea, amount remaining will be:

1.05 * 10²⁴ - 3 * 10²³ = (15.05 - 3) * 10²³ molecules of urea

Amount remaining = 12.05 * 10²³

Amount remaining = 1.205 * 10²⁴ molecules of urea

4 0
3 years ago
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