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umka21 [38]
3 years ago
8

During one month there were 7 days of precipitation.What if there had only been 3 days of precipitation that month?How would tha

t change the measures of center?
Mathematics
1 answer:
faust18 [17]3 years ago
7 0
We've hit on a case where a measure<span> of </span>center does<span> not provide all the information  spread or variability </span>there<span> is </span>in month-to-month precipitation<span>.  based on how busy each </span>month has been in<span> the past, lets managers plan  Unit 6: Standard Deviation | Student Guide | Page </span>3<span>  </span>If<span> you sum the deviations from the mean, (. ).</span>
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Lorenzo tiene 4 cajas de huevo, cada uno con 50 huevos y 3 cartones del mismo producto con 10 de ellos ¿Cuántos huevos hay en to
Bogdan [553]

Responder:

240 huevos

Explicación paso a paso:

Número de cajas de huevos = 4

Huevos por caja = 50

Total de huevos en caja = 50 * 4 = 200 huevos

Número de cajas = 3

Número de huevos por caja = 10

Total de huevos en caja = 10 * 4 = 40 huevos

Huevos totales = (huevos en caja + huevos en cartón)

Total = (200 + 40) = 240 huevos

3 0
3 years ago
Write the vector u as a sum of two orthogonal vectors, one of which is the vector projection of u onto v, proj,u
11Alexandr11 [23.1K]

Answer:

Take b = \frac{-17}{25}(7,1) as the projection of u onto v and w \frac{1}{25}(-31,217) as the vector such that b+w =u

Step-by-step explanation:

The formula of projection  of a vector u onto a vector v is given by

\frac{u\cdot v}{v\cdot v}v, where cdot is the dot product between vectors.

First, let b ve the projection of u onto v. Then

b = \frac{u\cdot v}{v\cdot v}v= \frac{-6\cdot 7+8\cdot 1}{7\cdot 7+1\cdot 1}(7,1) = \frac{-34}{50}(7,1) = \frac{-17}{25}(7,1)

We want a vector w, that is orthogonal to b and that b+w = u. From this equation we have that w = u-b = (-6,8)-\frac{-17}{25}(7,1)= \frac{1}{25}(-31,217)[/tex]

By construction, we have that w+b=u. We need to check that they are orthogonal. To do so, the dot product between w and b must be zero. Recall that if we have vectors a,b  that are orthogonal then for every non-zero escalar r,k the vector ra and kb are also orthogonal. Then, we can check if w and b are orthogonal by checking if the vectors (7,1) and (-31, 217) are orthogonal.

We have that (7,1)\cdot(-31,217) = 7\cdot -31 + 217 \cdot 1 = -217+217 =0. Then this vectors are orthogonal, and thus, w and b are orthogonal.

5 0
3 years ago
HELP HELP HELP thank you
sveta [45]
The point is now at (3,0).
4 0
3 years ago
Write the first four multiples of each number.<br><br>1. 3 <br>2. 4<br>3. 8 <br>4. 15
Levart [38]

Answer:

3, 6, 9, 12

4, 8, 12, 16

8, 16, 24, 32

15, 30, 45, 60

Step-by-step explanation:

multiply each number by itself

5 0
3 years ago
URGENT AND SIMPLE question pls:))) You dont have to do all of it, if you could just give me the equation for this problem, that
Mashcka [7]

If Ann can build the model in 3 hours, then in 1 hour she gets 1/3 of it done. Likewise, if Sam can build the model in 6 hours, then in 1 hour he gets 1/6 of it done. We are looking to find how long it takes when they combine their efforts, so we will add the two together and set it equal to 1/x, x being the number of hours it takes for both of them to get the whole job done. The equation then looks like this: \frac{1}{3}+\frac{1}{6}=\frac{1}{x}. You will have to find the common denominator to add those fractions, and once you do, cross multiply to solve for x.

5 0
3 years ago
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